php - 使用PHP XPatch在同一foreach循环中从多个域回显文本

Question

我正在做一个剪贴练习，它可以工作，但是我想不出一种以所需格式输出数据的方法：

quote quote quote quote quote : author
quote quote quote quote quote : author
quote quote quote quote quote : author

我只能得到：

quote quote quote quote quote
quote quote quote quote quote
quote quote quote quote quote
author
author
author

码：

$html = file_get_contents('http://www.brainyquote.com/authors/buddha');
$dom = new DOMDocument;
@$dom->loadHTML($html);

$classname1="b-qt";
$classname2="bq-aut";
$finder = new DomXPath($dom);
$quotes = $finder->query("//*[contains(@class, '$classname1')]//text()");
$authors = $finder->query("//*[contains(@class, '$classname2')]//text()");


foreach ($quotes as $quote){
    echo $quote->textContent . '<br>';
}

foreach ($authors as $author){
    echo $author->textContent . '<br>';
}

Answer 1

根据当前输出，您会发现两个数组具有相同数量的元素

因此，您可以：-

foreach ($quotes as $key=> $quote){
  echo $quote->textContent .' : '.$authors[$key]->textContent;
}

如果元素数量不同，则：-

$quote_count = count($quotes);
$author_count = count($authors);


if($quote_count > $author_count ){
    foreach ($quotes as $key =>$quote){
        echo $quote->textContent .' : '. $authors[$key]->textContent;
    }

}else {
    foreach ($authors as $key =>$author){
        echo $quote[$key]->textContent .' : '. $author->textContent;
    }
}