xcode - 设置 osx 的 map 以及用户当前位置

Question

问候专家，

据我所知，我们可以使用适用于 IOS 的谷歌地图 api 制作 map ，如下面的代码所示。

import UIKit
import GoogleMaps
/* For cocoa:
   Import Cocoa
   Import MapKit
*/
   class ViewController: NSViewController, CLLocationManagerDelegate {

@IBOutlet var mapView: MKMapView!
var locationManager = CLLocationManager()
var didFindMyLocation = false
var strForCurLatitude = "";
var strForCurLongitude = "";
var currentLocation = locManager.location!


override func viewDidLoad() {
    super.viewDidLoad()

    locationManager.delegate = self
    locationManager.requestWhenInUseAuthorization()
    locationManager.desiredAccuracy = kCLLocationAccuracyBest
    locationManager.distanceFilter = kCLDistanceFilterNone
    locationManager.startUpdatingLocation()
}

func locationManager(_ manager: CLLocationManager, didChangeAuthorization status: CLAuthorizationStatus) {
    if status == .authorizedWhenInUse {
        print("User allowed us to access location")
    }
}
func locationManager(_ manager: CLLocationManager, didFailWithError error: Error) {
    print("Error while get location \(error)")
}

func locationManager(_ manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
    let location: CLLocation? = locationManager.location
    let coordinate: CLLocationCoordinate2D? = location?.coordinate
    print(coordinate!)
    print(coordinate!.latitude)
    print(coordinate!.longitude)
    strForCurLatitude = "\(coordinate!.latitude)"
    strForCurLongitude = "\(coordinate!.longitude)"
    let camera = GMSCameraPosition.camera(withLatitude: coordinate!.latitude, longitude: coordinate!.longitude, zoom: 15)
    let mapView = GMSMapView.map(withFrame: .zero, camera: camera)
    mapView.isMyLocationEnabled = true
    self.view = mapView

    let marker = GMSMarker()
    marker.position = CLLocationCoordinate2DMake(coordinate!.latitude, coordinate!.longitude)
    marker.map = mapView
}


override var representedObject: Any? {
    didSet {
    // Update the view, if already loaded.
    }
}
}

但是当我在 osx 上尝试类似的方法时(区别在于我使用的是 Mapkit 而不是 google map )，它显示 requestWhenInUseAuthorization()' 不可用。我红色这条线How to get user location ? [macOS]但似乎还没有明确解决是否可以获取 osx 的当前位置。那么 macOS/cocoa 应用程序是否无法获取当前位置？如果不是，那么如何在 cocoa 应用程序中获取当前位置？

我很确定许多像我这样的 xcode 程序员都试图解决这个问题。任何答案你都会得到很大的赞赏。 :)

Answer 1

requestWhenInUseAuthorization 在 macOS 上不可用。

以下是 NSViewController 子类的源代码，该子类在 macOS 10.13.6 上的 Xcode 10.1 中成功检查位置管理器和当前位置:

import Cocoa
import MapKit
import CoreLocation

class MapViewController: NSViewController, CLLocationManagerDelegate {

    @IBOutlet weak var mapView: MKMapView!
    let locationManager = CLLocationManager()

    override func viewDidLoad() {
        super.viewDidLoad()

        locationManager.delegate = self
        locationManager.startUpdatingLocation()
    }

    func locationManager(_ manager: CLLocationManager, 
                        didChangeAuthorization status: CLAuthorizationStatus) {
        print("location manager auth status changed to:" )
        switch status {
            case .restricted:
                print("status restricted")
            case .denied:
                print("status denied")

        case .authorized:
                print("status authorized")
                let location = locationManager.location
                print("location: \(String(describing: location))")

            case .authorizedAlways:
                print("status authorized always")
            case .notDetermined:
                print("status not yet determined")
        }


    }

    func locationManager(_ manager: CLLocationManager, 
                            didFailWithError error: Error) {
        print( "location manager failed with error \(error)" )
    }
}

如果您在第一次启动应用程序时对“启用位置服务”提示选择"is"，则适用于 macOS。

请注意，您还需要文档中所示的 NSLocationWhenInUseUsageDescription 属性列表条目。

控制台输出(稍微混淆):

location manager auth status changed to: status not yet determined location manager auth status changed to: status authorized location: Optional(<+4X.48,-12X.62632228> +/- 65.00m (speed -1.00 mps / course -1.00) @ 11/3/18, 11:42:48 AM Pacific Daylight Time)