Flask-jwt 和 Flask-resftul 错误处理

Question

我正在使用 flask-jwt和 flask-restful

这就是 flask-jwt 处理错误的方式(取自其 github 存储库)，但没有一个让我获取 JWTError 的参数。

if auth is None:
        raise JWTError('Authorization Required', 'Authorization header was missing', 401, {
            'WWW-Authenticate': 'JWT realm="%s"' % realm
        })

parts = auth.split()

if parts[0].lower() != auth_header_prefix.lower():
    raise JWTError('Invalid JWT header', 'Unsupported authorization type')
elif len(parts) == 1:
    raise JWTError('Invalid JWT header', 'Token missing')
elif len(parts) > 2:
    raise JWTError('Invalid JWT header', 'Token contains spaces')

try:
    handler = _jwt.decode_callback
    payload = handler(parts[1])
except SignatureExpired:
        raise JWTError('Expired JWT', 'Token is expired', 401, {
            "WWW-Authenticate": 'JWT realm="{0}"'.format(realm)
        })
except BadSignature:
        raise JWTError('Invalid JWT', 'Token is undecipherable')

_request_ctx_stack.top.current_user = user = _jwt.user_callback(payload)

if user is None:
    raise JWTError('Invalid JWT', 'User does not exist')

以下是我尝试处理 JWTError 的不同方式

在 flask 中:

def handle_user_exception_again(e):
    if isinstance(e, JWTError):
        data = {'status_code': 1132, 'message': "JWTError already exists."}
        return jsonify(data), e.status_code, e.headers
    return e

app.handle_user_exception = handle_user_exception_again

在 flask-restful 中(handle_error)

class FlaskRestfulJwtAPI(Api):

def handle_error(self, e):
    if isinstance(e, JWTError):
        code = 400
        data = {'status_code': code, 'message': "JWTError already exists."}
    elif isinstance(e, KeyError):
        code = 400
        data = {'status_code': code, 'message': "KeyError already exists."}
    else:
        # Did not match a custom exception, continue normally
        return super(FlaskRestfulJwtAPI, self).handle_error(e)
    return self.make_response(data, code)

在 flask-restful (error_router) 中

class FlaskRestfulJwtAPI(Api):

def error_router(self, original_handler, e):
    print(type(e))
    if e is JWTError:#KeyError:
        data =  {
                "code":400,
                "message":"JWTError"
            }
        return jsonify(data), 400
    elif isinstance(e,KeyError):
        data =  {
            "code":400,
            "message":"KeyError"
        }
        return jsonify(data), 400
    else:
        return super(FlaskRestfulJwtAPI, self).error_router(original_handler, e)

Answer 1

我看到您正在尝试从这些错误中引发 HTTPException，这有助于将它们返回给用户。要引发 HTTP 异常，您可以捕获所有错误，如果它们是 JWTError 的实例，您可以使用如下函数将它们转换为 HTTPException 的实例:

def convert_to_http_exception(e):
    if isinstance(e, JWTError):
        jwtdescription = e.error + ": " + e.description
        http_exception = HTTPException(description=jwtdescription)
        http_exception.code = e.status_code
        return http_exception
    else:
        return e