objective-c - 如何将字符串转换为一系列击键？

Question

我正在使用CGPostKeyboardEvent((CGCharCode)0, (CGKeyCode)55, true);模拟按键，但假设我有一个字符串想要转换为按键。我如何将 NSString 分成单个字符，然后将它们转换为按键？谢谢!

编辑: 好的，我想我找到了解决方案，但我无法使语法正确。 Objective-C 真的让我发疯。

这是我的代码:

int stringLength = [theData length];
  for (int i = 1; i <= stringLength; i++) {
   char *currentCharacter = [theData characterAtIndex:i];
   CGPostKeyboardEvent((CGCharCode)0, (CGKeyCode)keyCodeForKeyString(currentCharacter), true);
}

-(int)keyCodeForKeyString:(char *)keyString
{
 if (strcmp(keyString, "a") == 0) return 0;
 if (strcmp(keyString, "s") == 0) return 1;
 if (strcmp(keyString, "d") == 0) return 2;
 if (strcmp(keyString, "f") == 0) return 3;
 if (strcmp(keyString, "h") == 0) return 4;
 if (strcmp(keyString, "g") == 0) return 5;
 if (strcmp(keyString, "z") == 0) return 6;
 if (strcmp(keyString, "x") == 0) return 7;
 if (strcmp(keyString, "c") == 0) return 8;
 if (strcmp(keyString, "v") == 0) return 9;
 // what is 10?
 if (strcmp(keyString, "b") == 0) return 11;
 if (strcmp(keyString, "q") == 0) return 12;
 if (strcmp(keyString, "w") == 0) return 13;
 if (strcmp(keyString, "e") == 0) return 14;
 if (strcmp(keyString, "r") == 0) return 15;
 if (strcmp(keyString, "y") == 0) return 16;
 if (strcmp(keyString, "t") == 0) return 17;
 if (strcmp(keyString, "1") == 0) return 18;
 if (strcmp(keyString, "2") == 0) return 19;
 if (strcmp(keyString, "3") == 0) return 20;
 if (strcmp(keyString, "4") == 0) return 21;
 if (strcmp(keyString, "6") == 0) return 22;
 if (strcmp(keyString, "5") == 0) return 23;
 if (strcmp(keyString, "=") == 0) return 24;
 if (strcmp(keyString, "9") == 0) return 25;
 if (strcmp(keyString, "7") == 0) return 26;
 if (strcmp(keyString, "-") == 0) return 27;
 if (strcmp(keyString, "8") == 0) return 28;
 if (strcmp(keyString, "0") == 0) return 29;
 if (strcmp(keyString, "]") == 0) return 30;
 if (strcmp(keyString, "o") == 0) return 31;
 if (strcmp(keyString, "u") == 0) return 32;
 if (strcmp(keyString, "[") == 0) return 33;
 if (strcmp(keyString, "i") == 0) return 34;
 if (strcmp(keyString, "p") == 0) return 35;
 if (strcmp(keyString, "RETURN") == 0) return 36;
 if (strcmp(keyString, "l") == 0) return 37;
 if (strcmp(keyString, "j") == 0) return 38;
 if (strcmp(keyString, "'") == 0) return 39;
 if (strcmp(keyString, "k") == 0) return 40;
 if (strcmp(keyString, ";") == 0) return 41;
 if (strcmp(keyString, "\\") == 0) return 42;
 if (strcmp(keyString, ",") == 0) return 43;
 if (strcmp(keyString, "/") == 0) return 44;
 if (strcmp(keyString, "n") == 0) return 45;
 if (strcmp(keyString, "m") == 0) return 46;
 if (strcmp(keyString, ".") == 0) return 47;

 fprintf(stderr, "keyString %s Not Found. Aborting...\n", keyString);
 exit(EXIT_FAILURE);
}

所以我的问题是，我如何获得 keyCodeForKeyString(currentCharacter)在 CGPostKeyboardEvent 的参数内？

Answer 1

这个问题是一场噩梦，因为有一些函数可以将按键代码转换为字符代码，但反之则不然。请记住，并非所有字符都可以键入，可以键入哪些字符取决于当前的键盘布局。

如果您的目标是使某些文本出现在另一个应用程序中，则无需使用 CGEventKeyboardSetUnicodeString 翻译单个字符即可实现此目的。然而，此功能的实现一直参差不齐，因此请务必在您关心的所有操作系统版本以及 Carbon 和 Cocoa 应用程序中进行测试。