python-3.x - 如何从复杂字典中提取嵌套数据并从中提取嵌套数据以构建新字典？

Question

如何从一个复杂的字典D中提取嵌套的数据，并从中提取出一个新的字典NS_D？

IN: D= {'10': [{'tea': ['indian', 'green']}], '13': [{'dancing': ['tango', 'step']}], '12': [{'walk': ['running', 'walking']}]}

OUT: NS_D = {'tea': ['indian', 'green'], 'dancing': ['tango', 'step'], 'walk': ['running', 'walking']}

Answer 1

您可以执行以下操作

如您所知，字典可以使用它们的键、它们的值或键和值来调用>称为项目(所有信息here)

In [78]: NS_D = {} 

In [79]: for keys in D.values(): #first loop: parsing through the values
    ...:     for key in keys:    #second loop: parsing through the keys
    ...:         for za,az in key.items(): #third loop: printing keys and values
    ...:             NS_D[za] = az  #you append the keys and values in the dictionary

In [80]: print(NS_D) 
{'tea': ['indian', 'green'], 'dancing': ['tango', 'step'], 'walk': ['running', 'walking']} 

少了一点 pythonic 但它有效。