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python-3.x - 无法使用Selenium(Python)从Google下拉菜单中进行选择

转载 作者:行者123 更新时间:2023-12-03 16:45:32 24 4
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我正在尝试使用Python自动执行Google专利网站上的搜索。这是网站https://patents.google.com/advanced的链接
我需要弄清楚如何从下拉菜单中进行选择。例如,从专利局下拉菜单中,我需要选择美国作为国家。

我尝试使用Selenium find_element_ by_xpath来确定下拉菜单。按照此网站上建议的解决方案,我尝试使用Selenium select_by visible_text单击菜单。我没有成功。

我对Python和html都是陌生的,因此任何线索将不胜感激。
这是我尝试过的Python代码,并从专利局下拉列表中选择了美国作为国家/地区。

#Identify the dropdown menu for Patent Office

off_element=driver.find_element_by_xpath("//dropdown-menu[@change-action='RESTRICT_OFFICE_MENU']/iron-dropdown/div[@id='contentWrapper']/div[@id='menu']/div[@class='style-scope dropdown-menu']")


#Declare the dropdown as an instance of the Select class.

patoff= Select(off_element)
patoff.selectByVisibleText("US")


这是我得到的错误

“ UnexpectedTagNameException:消息:选择仅适用于选择元素,不适用于div”

但是,我在html代码中看不到任何选择元素。我的xpath不正确吗?下拉列表不可见吗?在下面,我为下拉菜单粘贴了html代码。我不确定应该提供多少详细信息,所以我复制了整个路径。国家列表位于最底部。
谢谢!

<dropdown-menu show-label="true" multi="" label="Patent Office" change-action="RESTRICT_OFFICE_MENU" class="style-scope restrict-editor">

<span class="label style-scope dropdown-menu">
<span class="style-scope dropdown-menu">Patent Office</span>
<span id="selected" class="style-scope dropdown-menu" hidden="">
<span style="margin: 0px 4px 0px 2px" class="style-scope
dropdown-menu">·</span>
<span class="style-scope dropdown-menu"></span>
</span>
<iron-icon icon="icons:arrow-drop-down" class="style-scope
dropdown-menu x-scope iron-icon-0"><svg viewBox="0 0 24 24"
preserveAspectRatio="xMidYMid meet" focusable="false"
class="style-scope iron-icon" style="pointer-events: none;
display: block; width: 100%; height: 100%;"><g class="style-
scope iron-icon"><path d="M7 10l5 5 5-5z" class="style-scope
iron-icon"></path></g></svg>
</iron-icon><iron-icon icon="icons:arrow-drop-up" class="style-scope
dropdown-menu x-scope iron-icon-0" hidden=""><svg viewBox="0 0 24
24" preserveAspectRatio="xMidYMid meet" focusable="false"
class="style-scope iron-icon" style="pointer-events: none; display:
block; width: 100%; height: 100%;"><g class="style-scope iron-
icon"><path d="M7 14l5-5 5 5z" class="style-scope iron-icon"> .
</path></g></svg>
</iron-icon>
</span>
<iron-dropdown allow-outside-scroll="" horizontal-align="left"
vertical-align="top" class="style-scope dropdown-menu" aria-
disabled="false" aria-hidden="true" style="outline: none; display:
none;"

<div id="contentWrapper" class="style-scope iron-dropdown">
<div class="dropdown-content style-scope dropdown-menu"
slot="dropdown-content" id="menu" multi="">
<div class="style-scope dropdown-menu">

<div class="item style-scope dropdown-menu">WO</div>

<div class="item style-scope dropdown-menu">US</div>

<div class="item style-scope dropdown-menu">EP</div>

<div class="item style-scope dropdown-menu">JP</div>

<div class="item style-scope dropdown-menu">KR</div>

<div class="item style-scope dropdown-menu">CN</div>

<div class="item style-scope dropdown-menu">AE</div>

最佳答案

以下代码适用于我,使用Chrome驱动程序:

import time

import urllib.request

import urllib.response

import re

from selenium import webdriver

from selenium.webdriver.common.keys import Keys

from selenium.webdriver.support.ui import WebDriverWait

from selenium.webdriver.support import expected_conditions as EC

from selenium.webdriver.common.by import By

from selenium.webdriver.support.select import Select

from selenium.webdriver.support.ui import Select

from selenium.webdriver.common.action_chains import ActionChains

import webbrowser

import requests, sys

import requests, csv

from lxml import html

import lxml.html

import requests

Chrome = webdriver.Chrome(executable_path='enter_your_driver_file_path_here')

url = "https://patents.google.com/advanced"

Chrome.get(url)

#Find Patent Office Menu.
patent_menu = Chrome.find_element_by_xpath("//*/span[@class='style-scope dropdown-menu' and text()='Patent Office']")

#Open the Patent Office menu.
patent_menu.click()

#Wait long enough for the patent menu to open, before selecting the country.
Chrome.implicitly_wait(10)

#Find the patent country option, which in this case is the 'US'.
patent_country = Chrome.find_element_by_xpath("//*/div[@id='menu']/div[@class='style-scope dropdown-menu']/div[@class='item style-scope dropdown-menu' and text()='US']")

#Select the patent country option, which in this case is the 'US'.
patent_country.click()

关于python-3.x - 无法使用Selenium(Python)从Google下拉菜单中进行选择,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55769888/

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