spring-boot - Spring Boot : Could not resolve view with name 'index' in servlet with name 'dispatcherServlet'

Question

我正在尝试使用 spring boot 设置我的应用程序的主页..但我收到的错误是 无法解析名称为“dispatcherServlet”的 servlet 中名称为“index.html”的 View

我的代码如下

运行应用程序

@SpringBootApplication
public class RunApplication {

    static Logger logger = Logger.getLogger(RunNavneetApplication.class);

    public static void main(String[] args) {
        SpringApplication.run(RunNavneetApplication.class, args);
    }
}

应用程序属性

spring.mvc.view.prefix=/WEB-INF/view/
spring.mvc.view.suffix=.html

主 Controller .java

@Controller 
public class HomeController {
    @RequestMapping("/")
    public String index() {
        return "index";
    }
}

配置文件

@Configuration
@EnableWebMvc
public class WebConfig extends WebMvcConfigurerAdapter {

    @Override
    public void addCorsMappings(CorsRegistry registry) {
        registry.addMapping("/**");
    }

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/productImages/**")
        .addResourceLocations("file:/home/rahul/Desktop/product_images/")
        .setCachePeriod(0);
    }
}

pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>com.wocs</groupId>
  <artifactId>REST</artifactId>
  <version>0.0.1-SNAPSHOT</version>


<properties>
<java-version>1.8</java-version>
<service-version>0.1.36-SNAPSHOT</service-version>
</properties>  

  <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.0.2.RELEASE</version>
  </parent>

<dependencies>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-web</artifactId>
    </dependency>

    <dependency>
          <groupId>com.wocs</groupId>
          <artifactId>services</artifactId>
          <version>${service-version}</version>
    </dependency>

    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-jasper</artifactId>
        <scope>provided</scope>
    </dependency>

    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>jstl</artifactId>
    </dependency>

</dependencies>

请帮我解决这个问题.. 提前非常感谢...

Answer 1

对我来说(spring-boot-starter-parent version 2.0.5.RELEASE)它以这种方式改变了路径:src/main/resources/网络信息 /view/index.html →src/main/resources/ META-INF/资源 /view/index.html (出于某种原因，它似乎不喜欢 WEB-INF 名称，它需要嵌套的 resources 目录)。
它似乎也适用于 src/main/ 资源/资源 /view/index.html在这些情况下，您甚至不需要添加 @EnableWebMvc注释和实现 WebMvcConfigurer (在application.properties中配置的前缀和后缀就足够了)。
我还在我的回答中添加了关于从 Spring Boot 引用指南中获取的 MVC 配置的说明:

27.1.1 Spring MVC Auto-configuration

If you want to keep Spring Boot MVC features and you want to add additional MVC configuration [...] you can add your own @Configuration class of type WebMvcConfigurer but without @EnableWebMvc.

If you want to take complete control of Spring MVC, you can add your own @Configuration annotated with @EnableWebMvc.

76.7 Switch off the Default MVC Configuration

The easiest way to take complete control over MVC configuration is to provide your own @Configuration with the @EnableWebMvcannotation. Doing so leaves all MVC configuration in your hands.