javascript - 在Javascript中生成4个随机数，它们添加到某个值

Question

我想要一些 javascript，它可以让我生成 4 个随机数，它们加起来为某个值，例如

如果

max = 20

然后

num1 = 4
num2 = 4
num3 = 7
num4 = 5

或者

max = 36

然后

num1 = 12
num2 = 5
num3 = 9
num4 = 10

到目前为止我所拥有的是...

var maxNum = 20;
var quarter;
var lowlimit;
var upplimit;
var num1 = 1000;
var num2 = 1000;
var num3 = 1000;
var num4 = 1000;
var sumnum = num1+num2+num3+num4;

quarter = maxNum * 0.25;
lowlimit = base - (base * 0.5);
upplimit = base + (base * 0.5);

if(sumnum != maxNum){
    num1 = Math.floor(Math.random()*(upplimit-lowlimit+1)+lowlimit);
    num2 = Math.floor(Math.random()*(upplimit-lowlimit+1)+lowlimit);
    num3 = Math.floor(Math.random()*(upplimit-lowlimit+1)+lowlimit);
    num4 = Math.floor(Math.random()*(upplimit-lowlimit+1)+lowlimit);
}

Answer 1

此代码将创建四个整数，总和为最大数且不为零

var max = 36;
var r1 = randombetween(1, max-3);
var r2 = randombetween(1, max-2-r1);
var r3 = randombetween(1, max-1-r1-r2);
var r4 = max - r1 - r2 - r3;


function randombetween(min, max) {
  return Math.floor(Math.random()*(max-min+1)+min);
}

编辑:这个将创建 thecount总和为 max 的整数个数并将它们返回到一个数组中(使用上面的 randombetween 函数)

function generate(max, thecount) {
  var r = [];
  var currsum = 0;
  for(var i=0; i<thecount-1; i++) {
     r[i] = randombetween(1, max-(thecount-i-1)-currsum);
     currsum += r[i];
  }
  r[thecount-1] = max - currsum;
  return r;
}