c# - 将多个参数传递给 BeginInvoke()

Question

我有简单的(我认为的)逻辑。

public static void NotifyAboutNewJob(int jobId, bool forceSending = false)
{
        Action<int> notifier = SendAppleNotifications;
        notifier.BeginInvoke(jobId, null, null);
}

方法 SendAppleNotifications 有一个参数a，很容易将它传递给 BeginInvoke .现在我添加了第二个参数 forceSending .和问题 - 我不知道如何将它传递给 BeginInvoke .

我应该将它作为第三个参数传递给 object ?

private static void SendAppleNotifications(int jobId, bool forceSending = false){...}

或者这是答案:

Action<int, bool> notifier = SendAppleNotifications;
notifier.BeginInvoke(jobId, forceSending, null, null);

Answer 1

更改您的 Action<int>至 Action<int, bool>

Action<int, bool> notifier = SendAppleNotifications;
notifier.BeginInvoke(jobId, forceSending, null, null); // You can now pass true or false as 2nd parameter.

那么它应该可以正常工作。