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xml - 具有不同深度的 xml 文档的 xpath

转载 作者:行者123 更新时间:2023-12-03 16:27:40 26 4
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我有一个 xml 文档,其中有固定的结构,但深度是变化的,例如:-

  1. It has main node <project>.
  2. it has child node <namespace> that may be repeated multiple times. And there may come some new tags before or after <namespace>.
<project>
<newtag>
<namespace>
<namespace>
..........
</namespace>
</namespace>
</newtag>
</project>
  1. After multiple namespace there are two more tags of my interest <querySubject> and <queryItem>

我正在使用特定的 XPATH 在 queryItem 标签中搜索文本:-

/project/namespace/namespace/querySubject/queryItem[contains(., 'searchTerm')]/ancestor-or-self::*/name

对于下面给出的特定结构,我的 Xpath 工作正常:-

<project>
<namespace>
<name locale="en">Test</name>
<lastChanged>2016-01-12T12:42:46</lastChanged>
<namespace>
<name locale="en">Database Layer</name>
<querySubject status="valid">
<name locale="en">qskxyz</name>
<queryItem>
<name locale="en">qixyz</name>
<hello>searchTerm</hello>
</queryItem>
</querySubject>
</namespace>
</namespace>
<namespace>
<name locale="en">Test</name>
<lastChanged>2016-01-12T12:42:46</lastChanged>
<namespace>
<name locale="en">Database Layer</name>
<querySubject status="valid">
<name locale="en">qsxyz</name>
<queryItem>
<name locale="en">myName</name>
<hello>...Hi there..</hello>
</queryItem>
</querySubject>
</namespace>
</namespace>
</project>

但如果如上几点所述发生变化,则无法正常工作。任何建议

编辑 1.

我的观察有些失误

我的实际项目标签是

<project containsDynamicContent="false" xmlns="http://www.developer.cognos.com/schemas/bmt/60/7" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.developer.cognos.com/schemas/bmt/60/7 BMTModelSpecification.xsd">

但是在开发中我采用简单的 <project></project>

这影响了我的 Xpath 不工作。我在 Xpath 下尝试过的任何建议但这也不起作用,我无法更改我的 xml 标记。我已经尝试过这个 xpath :-

//namespace//querySubject/queryItem[contains(.,'searchTerm')]/ancestor-or-self::*/name 

最佳答案

基本上,XPath 表达式是:

/x:project//x:namespace//x:querySubject/x:queryItem[contains(.,'searchTerm')]/ancestor-or-self::*/x:name

然后需要关联命名空间http://www.developer.cognos.com/schemas/bmt/60/7带有前缀 x .


我将留给您一个 Java (1.7) 代码片段作为示例。这注册了一个 NamespaceContext使用 XPath 表达式,它解析前缀的 namespace (在本例中为 x)。该片段是一个简单的例子,它甚至不检查传递给 NamespaceContext.getNamespaceURI 的前缀。 .典型的实现使用映射将 URI 映射到前缀。

其他开发环境应该具有类似的功能。


import java.io.StringReader;
import java.util.Iterator;
import javax.xml.namespace.NamespaceContext;
import javax.xml.xpath.*;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;

public class XPathInXmlns {
private static final String xml=
"<project containsDynamicContent=\"false\" xmlns=\"http://www.developer.cognos.com/schemas/bmt/60/7\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xsi:schemaLocation=\"http://www.developer.cognos.com/schemas/bmt/60/7 BMTModelSpecification.xsd\">"+
" <namespace>"+
" <name locale=\"en\">Test</name>"+
" <lastChanged>2016-01-12T12:42:46</lastChanged>"+
" <namespace>"+
" <name locale=\"en\">Database Layer</name>"+
" <querySubject status=\"valid\">"+
" <name locale=\"en\">qskxyz</name>"+
" <queryItem>"+
" <name locale=\"en\">qixyz</name>"+
" <hello>searchTerm</hello>"+
" </queryItem>"+
" </querySubject>"+
" </namespace>"+
" </namespace>"+
" <namespace>"+
" <name locale=\"en\">Test</name>"+
" <lastChanged>2016-01-12T12:42:46</lastChanged>"+
" <namespace>"+
" <name locale=\"en\">Database Layer</name>"+
" <querySubject status=\"valid\">"+
" <name locale=\"en\">qsxyz</name>"+
" <queryItem>"+
" <name locale=\"en\">myName</name>"+
" <hello>...Hi there..</hello>"+
" </queryItem>"+
" </querySubject>"+
" </namespace>"+
" </namespace>"+
" </project>";

private static final String xpathExpr=
"/x:project//x:namespace//x:querySubject/x:queryItem[contains(.,'searchTerm')]/ancestor-or-self::*/x:name/text()";

public static void main(String[] args) {
try {
XPath xpath = XPathFactory.newInstance().newXPath();
xpath.setNamespaceContext(new NamespaceContext() {
@Override
public Iterator getPrefixes(String namespaceURI) {
return null;
}
@Override
public String getPrefix(String namespaceURI) {
return null;
}
@Override
public String getNamespaceURI(String prefix) {
return "http://www.developer.cognos.com/schemas/bmt/60/7";
}
});
XPathExpression expr = xpath.compile(xpathExpr);
NodeList nodeList = (NodeList) expr.evaluate(new InputSource(new StringReader(xml)),XPathConstants.NODESET);
for( int i = 0; i != nodeList.getLength(); ++i )
System.out.println(nodeList.item(i).getNodeValue());
} catch (XPathExpressionException e) {
e.printStackTrace();
}
}
}

输出:

Test
Database Layer
qskxyz
qixyz

关于xml - 具有不同深度的 xml 文档的 xpath,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35694268/

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