xml - XSLT 将 xml 转换为 xml 提取特定值并映射到新格式

Question

我正在寻找有关 XSLT 的帮助，以将一个 xml 文件转换为另一种格式。

输入的xml文件如下:

<PATIENTLIST ELAPSEDMS="234" >
    <PATIENT ID="MGH000007">
        <ADDRESS1>550 BREZHNEV ST</ADDRESS1>
        <ADDRESS2></ADDRESS2>
        <CITY>MOSCOW</CITY>
        <STATE>MA</STATE>
        <ZIP>02139</ZIP>
        <COUNTRY ISO3166-1="USSR"></COUNTRY>
        <DATEOFBIRTH>1934/04/10</DATEOFBIRTH>
        <DAYPHONE>(617) 111-1111 </DAYPHONE>
        <FIRSTNAME>TEST</FIRSTNAME>
        <HOMEPHONE>(617) 111-1111</HOMEPHONE>
        <LASTNAME>TEST MGH</LASTNAME>
        <LIMITEDACCESS>False</LIMITEDACCESS>
        <MARITALSTATUS>SINGLE</MARITALSTATUS>
        <MEDICALRECORDNUMBERS>
            <MEDICALRECORDNUMBER>
                <SITE>BWH</SITE>
                <STATUS>A</STATUS>
                <VALUE>0000007</VALUE>
            </MEDICALRECORDNUMBER>
            <MEDICALRECORDNUMBER>
                <SITE>BWI</SITE>
                <STATUS>A</STATUS>
                <VALUE>0000007</VALUE>
            </MEDICALRECORDNUMBER>
            <MEDICALRECORDNUMBER>
                <SITE>MEEI</SITE>
                <STATUS>A</STATUS>
                <VALUE>0000007</VALUE>
            </MEDICALRECORDNUMBER>
            <MEDICALRECORDNUMBER>
                <SITE>MGH</SITE>
                <STATUS>A</STATUS>
                <VALUE>0000007</VALUE>
            </MEDICALRECORDNUMBER>
            <MEDICALRECORDNUMBER>
                <SITE>SHC</SITE>
                <STATUS>A</STATUS>
                <VALUE>0000007</VALUE>
            </MEDICALRECORDNUMBER>
            <MEDICALRECORDNUMBER>
                <SITE>OLD #</SITE>
                <STATUS>M</STATUS>
                <VALUE>0000007</VALUE>
            </MEDICALRECORDNUMBER>
        </MEDICALRECORDNUMBERS>
        <MIDDLEINITIAL>R</MIDDLEINITIAL>
        <MOTHERSMAIDENNAME></MOTHERSMAIDENNAME>
        <MRNR>0000007</MRNR>
        <NAME>TEST MGH, TEST R</NAME>
        <NAMESUFFIX></NAMESUFFIX>
        <NAMEPREFIX></NAMEPREFIX>
        <PRIMARYCAREPROVIDERID>512513</PRIMARYCAREPROVIDERID>
        <PRIMARYLANGUAGE>ENGLISH</PRIMARYLANGUAGE>
        <RACE CODE1="BLACK" CODE2="" FREETEXT="">BLACK</RACE>
        <ETHNICITY CODE1="AFRICAN AMERICAN" CODE2="" FREETEXT="">AFRICAN AMERICAN</ETHNICITY>
        <RELIGION>NO PREFERENCE</RELIGION>
        <SEX>M</SEX>
        <SSN></SSN>
        <UID>101662537</UID>
        <VETERAN>NO</VETERAN>
    </PATIENT>
</PATIENTLIST>

输出文件需要如下所示:

<?xml version="1.0" encoding="utf-8" ?>
<eCliPSEDataIntegrationServiceRequest xmlns="http://iocent.com/eCliPSEDataIntegrationServiceRequest.xsd">
    <PatientIdentifierRecord MedicalRecordNumber="MGH000007" LastName="Person" FirstName="Test" MiddleInitial="A" DateOfBirth="04/10/1934" Operation="Add" OverwriteExistingData="true" />
    <PatientDataRecord MedicalRecordNumber="MGH000007" ParameterName="Gender" ParameterValue="2" TimeStamp="8/30/2011" Operation="Add" OverwriteExistingData="true" />
    <PatientDataRecord MedicalRecordNumber="MGH000007" ParameterName="Race" ParameterValue="1" TimeStamp="8/30/2011" Operation="Add" OverwriteExistingData="true" />
</eCliPSEDataIntegrationServiceRequest>

所以我想拔出

患者 ID 并将其用作 MedicalRecordNumber= 值

DATEOFBIRTH 节点作为 DateOfBirth 值 - 格式从 YYYY/MM/DD 更改为 MM/DD/YYYY

FIRSTNAME 节点成为 FirstName 的值

LASTNAME 节点成为 LastName 的值

MIDDLEINITIAL 节点成为 MiddleInitial 的值

SEX 节点变为 Gender Male=1, Female=2 的值

RACE 节点变为 Value for Race - 基于查找表(高加索人 = 1，非裔美国人 = 2 等) -

所以我需要提取这些值，更改格式，在某些情况下进行类似表格的翻译(针对性别和种族)，然后以新格式写出文件。

我仅限于 XSLT 1.0

我对 XSLT 很陌生，因此将不胜感激任何帮助!!!

谢谢!

Answer 1

我很感激我在上面收到的开始。我在下面发布了我想出的解决问题的 xslt:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:variable name='newline'><xsl:text> 
</xsl:text>
</xsl:variable>

<xsl:variable name='MRN'>
    <xsl:value-of select="PATIENTLIST/PATIENT/@ID"/>
</xsl:variable>

<xsl:variable name='Gender'>
    <xsl:if test="PATIENTLIST/PATIENT/SEX='M'">1</xsl:if>
    <xsl:if test="PATIENTLIST/PATIENT/SEX='F'">2</xsl:if>
</xsl:variable>

 <xsl:variable name='RaceIn'>
   <xsl:value-of select="PATIENTLIST/PATIENT/RACE"/>
 </xsl:variable>  

<xsl:variable name='Race'>
  <xsl:choose>
    <xsl:when test="$RaceIn='WHITE'">1</xsl:when>
    <xsl:when test="$RaceIn='BLACK'">2</xsl:when>
    <xsl:when test="$RaceIn='HISPANIC'">3</xsl:when>
    <xsl:when test="$RaceIn='ASIAN'">4</xsl:when>
    <xsl:when test="$RaceIn='NATIVE AMERICAN'">5</xsl:when>
    <xsl:when test="$RaceIn='INDIAN'">5</xsl:when>
    <xsl:otherwise>7</xsl:otherwise>
  </xsl:choose>
</xsl:variable>

 <xsl:variable name='CurrDate'>
    <xsl:value-of select="'MM/DD/YYY'"/>
</xsl:variable>

<xsl:variable name='Operation'>
    <xsl:value-of select="'Add'"/>
</xsl:variable>

<xsl:variable name='Overwrite'>
    <xsl:value-of select="'true'"/>
</xsl:variable>




  <xsl:template match="/">
    <xsl:text>
    </xsl:text>
      <eCliPSEDataIntegrationServiceRequest >
        <xsl:text>
        </xsl:text>
        <PatientIdentifierRecord>
          <xsl:attribute name="MedicalRecordNumber">
            <xsl:value-of select="$MRN"/>
          </xsl:attribute>
          <xsl:attribute name="LastName">
            <xsl:value-of select="PATIENTLIST/PATIENT/LASTNAME"/>
          </xsl:attribute>
          <xsl:attribute name="FirstName">
            <xsl:value-of select="PATIENTLIST/PATIENT/FIRSTNAME"/>
          </xsl:attribute>
          <xsl:attribute name="MiddleInitial">
            <xsl:value-of select="PATIENTLIST/PATIENT/MIDDLEINITIAL"/>
          </xsl:attribute>
          <xsl:attribute name="DateOfBirth">
            <xsl:value-of select="PATIENTLIST/PATIENT/DATEOFBIRTH"/> <!-- do we need to change the date format?-->
          </xsl:attribute>
          <xsl:attribute name="Operation">
            <xsl:value-of select="$Operation"/>
          </xsl:attribute>
          <xsl:attribute name="OverwriteExistingData">
            <xsl:value-of select="$Overwrite"/>
          </xsl:attribute>
        </PatientIdentifierRecord>
        <xsl:text>
            </xsl:text>
          <PatientDataRecord>
            <xsl:attribute name="MedicalRecordNumber">
              <xsl:value-of select="$MRN"/>
            </xsl:attribute>
            <xsl:attribute name="ParameterName">
              <xsl:value-of select="'Gender'"/>
            </xsl:attribute>
            <xsl:attribute name="ParameterValue">
              <xsl:value-of select="$Gender"/>
            </xsl:attribute>
            <xsl:attribute name="Timestamp">
              <xsl:value-of select="$CurrDate"/>
            </xsl:attribute>
            <xsl:attribute name="Operation">
              <xsl:value-of select="$Operation"/>
            </xsl:attribute>
            <xsl:attribute name="OverwriteExistingData">
              <xsl:value-of select="$Overwrite"/>
            </xsl:attribute>
          </PatientDataRecord>
        <xsl:text>
            </xsl:text>
        <PatientDataRecord>
          <xsl:attribute name="MedicalRecordNumber">
            <xsl:value-of select="$MRN"/>
          </xsl:attribute>
          <xsl:attribute name="ParameterName">
            <xsl:value-of select="'Race'"/>
          </xsl:attribute>
          <xsl:attribute name="ParameterValue">
            <xsl:value-of select="$Race"/>           <!-- this needs to be transformed based on race table and race_7_groups parameter -->
          </xsl:attribute>
          <xsl:attribute name="Timestamp">
            <xsl:value-of select="$CurrDate"/>                  <!-- how do i get the current date?-->
          </xsl:attribute>
          <xsl:attribute name="Operation">
            <xsl:value-of select="$Operation"/>
          </xsl:attribute>
          <xsl:attribute name="OverwriteExistingData">
            <xsl:value-of select="$Overwrite"/>
          </xsl:attribute>
        </PatientDataRecord>
        <xsl:text>
    </xsl:text>
      </eCliPSEDataIntegrationServiceRequest>
  </xsl:template>
</xsl:stylesheet>

我仍在研究获取当前日期的解决方案。我看过的选项
- 作为参数传入
- 编写脚本函数来获取当前日期

另外，我不确定是否需要将日期格式从 YYYY/MM/DD 更改为 MM/DD/YYYY。

如果有人对上述两个主题有一些建议，他们将受到欢迎。

谢谢