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cocoa - 不 initWithWindowNibName 设置窗口字段

转载 作者:行者123 更新时间:2023-12-03 16:20:34 32 4
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我正在尝试使用以下代码来工作。它第一次执行预期的操作,打开一个窗口并将其设为前窗口,但是当随后调用它时, orderFront: 不起作用,因为 window 为 nil。为什么 initWithWindowNibName: 不设置从 initWithNibName: 返回的 NSWindowController 对象的窗口字段?

//
// CustomerCard.m
// POSWonder
//
// Created by kaydell on 2/26/12.
// Copyright 2012 Kaydell Leavitt. All rights reserved.
//

#import "CustomerCard.h"

@implementation CustomerCard

// declare customerCard as a static variable
static CustomerCard* customerCard;

+(void) show {

// if the customer card isn't instantiated, then instantiate it
if (customerCard == nil) {
customerCard = [[CustomerCard alloc] initWithWindowNibName:@"CustomerCard"];
if (!customerCard.window) {
NSLog(@"Why is window nil here?"); // <<<<<<<<<<< This line gets called <<<<<
}
}

// show the customer card and make it the front window
[customerCard showWindow:self];
[customerCard.window orderFront:self]; // <<<<<<<< This line doesn't seem to do anything

}

-(void) dealloc {
customerCard = nil;
[super dealloc];
}

@end

最佳答案

在 Interface Builder 中,您需要取消选中标有“关闭时释放”的框。如果启用此复选框,窗口将被释放,并可能在关闭时被释放。

如果您想保留窗口,您不希望出现这种行为,因此您需要将其关闭。

关于cocoa - 不 initWithWindowNibName 设置窗口字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9969394/

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