PHP、XML 和 XPath : Display specific nodes

Question

我正在努力完成一项任务。我正在尝试创建一个仅显示 Journal 元素的函数，其中 Author1/Auth1 是作者之一。我确实列出了三个 Journal 元素，但我只能将每个 Journal 分隔成一个新行。 我无法将结果中的每个 Journal-child(最好在值旁边加上文本)分隔到新行 (<br />) .

我有以下 XML 文档:

<Journals>
    <Journal>
        <Title>Title1</Title>
        <AuthorName>Author1</AuthorName> 
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Author3</AuthorName>
        <JournalName>One</JournalName>
    </Journal>
    <Journal>
        <Title>Title2</Title>
        <AuthorName>Author2</AuthorName>
        <AuthorName>Author1</AuthorName>
        <JournalName>Two</JournalName>
    </Journal>
    <Journal>
        <Title>Title3</Title>
        <AuthorName>Author3</AuthorName>
        <JournalName>Three</JournalName>
    </Journal>
    <Journal>
        <Title>Title4</Title>
        <AuthorName>Author3</AuthorName> 
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Author4</AuthorName>
        <JournalName>Four</JournalName>
    </Journal>
    <Journal>
        <Title>Title5</Title>
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Auth1</AuthorName>
        <JournalName>Five</JournalName>
    </Journal>
    <Journal>
        <Title>Title6</Title>
        <AuthorName>Author2</AuthorName> 
        <AuthorName>Author3</AuthorName>
        <JournalName>Six</JournalName>
    </Journal>
</Journals>

以及以下 PHP 文档:

<?php
  header('Content-Type: text/html; charset=utf-8');
  error_reporting(E_ERROR | E_WARNING | E_PARSE);


/* FUNCTION FOR ALL ARTICLES PUBLISHED BY Author1 */
  function taskOne()              
    {   
    $doc = new DOMDocument();
    $doc->load("file.xml"); 
    $xml = new DOMXPath($doc);

    $query = $xml->evaluate("/Journals/Journal/AuthorName[contains(. , 'Author1') or contains(. , 'Auth1')]/..");
    foreach ($query as $temp)
      {
      echo $temp->nodeValue . "<br />";
      }
    }
    taskOne();
?>

现在另一个问题:如何使用 XPath 查询:/Journals/Journal[contains(AuthorName, 'Author1') or contains(AuthorName, 'Auth1')]只列出 Author1 是第一作者的期刊，而不列出他是二号或三号 sibling 的期刊？这是 XPath 查询的最终输出: /Journals/Journal/AuthorName[contains(. , 'Author1') or contains(. , 'Auth1')]/..

Title1 Author1 Author2 Author3 One 
Title2 Author2 Author1 Two 
Title5 Author2 Auth1 Five

这里是 XPath 查询的最终输出: /Journals/Journal[contains(AuthorName, 'Author1') or contains(AuthorName, 'Auth1')]

Title1 Author1 Author2 Author3 One 

澄清一下，这是我想要实现的目标:

Title: Title1 
Journal author: Author1 
Journal author: Author2 
Journal author: Author3 
Journal name:   One

Title: Title2
Journal author: Author2 
Journal author: Author1 
Journal name:   Two 

Title: Title5 
Journal author: Author2 
Journal author: Auth1 
Journal name:   Five

Answer 1

您可以只针对 <Journal>哪个有 child <AuthorName>包含您想要的那根针。你已经很接近了:

$doc = new DOMDocument();
$doc->loadXML($xml_string);
$xpath = new DOMXpath($doc);

$query = "//Journal[AuthorName[contains(., 'Author1') or contains(., 'Auth1')]]";

$journals = $xpath->query($query);
if($journals->length > 0) {
    foreach($journals as $journal) { // for each of the journal found
        foreach($journal->childNodes as $e) { // loop all its nodes/children
            if(isset($e->tagName)) {
                echo "$e->tagName: " . $e->nodeValue . '<br/>';
            }
        }
        echo '<br/>';
    }
}

Sample Output