python - Python-randint()返回空范围，崩溃错误

Question

我已经能够在扑克程序中多次重复此错误，并尝试了各种失败的解决方案。这是最新的:

Traceback (most recent call last):
  File "C:\Users\Pangloss\Desktop\tgchanpoker\poker.py", line 1868, in <module>
    if __name__ == '__main__': main()
  File "C:\Users\Pangloss\Desktop\tgchanpoker\poker.py", line 1866, in main
    mainGame = Game(opponent)
  File "C:\Users\Pangloss\Desktop\tgchanpoker\poker.py", line 1443, in __init__
    if randint(1,betCheck+(10-handValue[1]))<5 or gameStage == "bettingStay":
  File "C:\Python27\lib\random.py", line 241, in randint
    return self.randrange(a, b+1)
  File "C:\Python27\lib\random.py", line 217, in randrange
    raise ValueError, "empty range for randrange() (%d,%d, %d)" % (istart, istop, width)
ValueError: empty range for randrange() (1,-7, -8)

这是相关的代码:

                    handValue = checkHand(opponent.cards.cards)
                    if gameStage == "betting" or gameStage == "final" or gameStage == "finalresponding":
                        betCheck = 18-handValue[1]-round(betAmount/(setMax/5))+opponent.brashness
                    elif gameStage == "extendedFinal":
                        betCheck = 16-handValue[1]-round(betAmount/(setMax/5))+opponent.brashness-(pot/100)
                    else:
                        betCheck = 16-handValue[1]-round(betAmount/(setMax/5))+opponent.brashness
                    foldCheck = 16-handValue[1]-round(betAmount/(setMax/3))+opponent.brashness+(pot/100)
                    if randint(1,betCheck+(10-handValue[1]))<5 or gameStage == "bettingStay":

Answer 1

此代码

randint(1,betCheck+(10-handValue[1]))

给你这个

randrange(1,-7,-8)

这意味着 betCheck+(10-handValue[1])给您-8

该范围根本不会给您任何数字，因为betCheck +(10-handValue [1]))为负数，并且该范围无效

您需要检查设置betcheck和handvalue [1]的代码，以了解为什么它是如此负数