typescript - 重命名 typescript 对象类型的键

Question

我有这个:

type Two = {
  one: number,
  two: string,
  three: boolean
}

我希望它创建一个看起来像这样的类型:

type RenamedTwo = {
  one: number,
  two: string,
  four: boolean // difference
}

尝试以这种方式创建它:

type Rename<T, K extends keyof T, N> = Pick<T, Exclude<keyof T, K>> & { [N]: T[K] }

尝试使用这种方式:

type Renamed = Rename<Two, 'three', 'four'>

但是TSlint将 [N]标记为错误并给出了以下错误消息:

[ts] A computed property name in a type literal must refer to an expression whose type is a literal type or a 'unique symbol' type. [ts] 'N' only refers to a type, but is being used as a value here.

Answer 1

您还需要对重命名的属性使用映射类型:

type Two = {
    one: number,
    two: string,
    three: boolean
}


type Rename<T, K extends keyof T, N extends string> = Pick<T, Exclude<keyof T, K>> & { [P in N]: T[K] }

type Renamed = Rename<Two, 'three', 'four'>

请注意，如果您提供更多属性，则此操作将无法按预期进行:

type Renamed = Rename<Two, 'two'  |'three' , 'four' | 'five'> // will be Pick<Two, "one"> & {
//    four: string | boolean;
//    five: string | boolean;
// }