cocoa - UIKit 的 [NSString sizeWithFont :constrainedToSize:] in AppKit

Question

AppKit(适用于 Mac OS X 上的 Cocoa)中是否有任何等效方法与 UIKit 的 [NSString sizeWithFont:constrainedToSize:] 执行相同的操作？

如果没有，我怎样才能获得渲染受宽度/高度限制的特定字符串所需的空间量？

更新:下面是我正在使用的代码片段，我希望它能产生我想要的结果。

NSDictionary *attributes = [NSDictionary dictionaryWithObjectsAndKeys:
                            [NSFont systemFontOfSize: [NSFont smallSystemFontSize]], NSFontAttributeName,
                            [NSParagraphStyle defaultParagraphStyle], NSParagraphStyleAttributeName,
                            nil];
NSSize size = NSMakeSize(200.0, MAXFLOAT);
NSRect bounds;

bounds = [@"This is a really really really really really really really long string that won't fit on one line"
             boundingRectWithSize: size
             options: NSStringDrawingUsesFontLeading
             attributes: attributes];

NSLog(@"height: %02f, width: %02f", bounds.size.height, bounds.size.width);

我预计输出宽度将为 200，高度将大于单行的高度，但它会产生:

height: 14.000000, width: 466.619141

谢谢!

Answer 1

试试这个:

bounds = [value boundingRectWithSize:size options:NSLineBreakByWordWrapping | NSStringDrawingUsesLineFragmentOrigin attributes:attributes];