cocoa - 在 Mac OS X 中以编程方式获取屏幕尺寸

Question

我可以使用以下方法返回屏幕尺寸:

- (void) getScreenResolution {

    NSArray *screenArray = [NSScreen screens];
    NSScreen *mainScreen = [NSScreen mainScreen];
    unsigned screenCount = [screenArray count];
    unsigned index  = 0;

    for (index; index < screenCount; index++)
    {
      NSScreen *screen = [screenArray objectAtIndex: index];
      NSRect screenRect = [screen visibleFrame];
      NSString *mString = ((mainScreen == screen) ? @"Main" : @"not-main");

      NSLog(@"Screen #%d (%@) Frame: %@", index, mString, NSStringFromRect(screenRect));
    }
}

输出:

Screen #0 (Main) Frame: {{0, 4}, {1344, 814}}

是否可以将 {1344, 814} 格式设置为 1344x814？

<小时/>

编辑:

这非常有效:

- (NSString*) screenResolution {

    NSRect screenRect;
    NSArray *screenArray = [NSScreen screens];
    unsigned screenCount = [screenArray count];
    unsigned index  = 0;

    for (index; index < screenCount; index++)
    {
        NSScreen *screen = [screenArray objectAtIndex: index];
        screenRect = [screen visibleFrame];
    }

    return [NSString stringWithFormat:@"%.1fx%.1f",screenRect.size.width, screenRect.size.height];
}

Answer 1

在 Swift 4.0 中你可以获取主屏幕的屏幕尺寸:

if let screen = NSScreen.main {
    let rect = screen.frame
    let height = rect.size.height
    let width = rect.size.width
}

如果您要查找特定现有窗口的屏幕大小，您可以通过以下方式获取:

var window: NSWindow = ... //The Window laying on the desired screen
var screen = window.screen!
var rect = screen.frame
var height = rect.size.height
var width = rect.size.width