delphi - 检查字符是否为换行符

Question

你好，我有一个简单的程序，它计算给定文本中的字符，直到行为空行，仅包含新行

var
  znaki: array['a'..'z'] of integer = (0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0);
  napis: String;
  maly: String;
  dlugosc: Integer;
  znak: char;


begin
napis := 'a';
while napis[1] <> '#13#10'do
begin
  readln(napis);
  maly:=LowerCase(napis);
  for dlugosc:=(length(maly)) downto 1 do
begin
znaki[maly[dlugosc]]:=znaki[maly[dlugosc]]+1;
  end;
  for znak:='a' to 'z' do
    writeln(znak, ' ', znaki[znak]);
  end;

end.  

它在 while 条件下失败，我不知道为什么。请给我线索

Answer 1

一个字符，napis[1]；不能是 2 个字符 #13 和 #10...

所以，我会这样做:

var
  znaki: array['a'..'z'] of integer = (0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0);
  napis: String;
  maly: String;
  dlugosc: Integer;
  znak: char;


begin
napis := 'a';
while ((Length(napis) > 0)) do
begin
  readln(napis);
//  napis := StringReplace(napis, #13#10, #10, [rfReplaceAll]);  //useless for a console readln
  maly:=LowerCase(napis);
  for dlugosc:=(length(maly)) downto 1 do
  begin
    znaki[maly[dlugosc]]:=znaki[maly[dlugosc]]+1;
  end;
  for znak:='a' to 'z' do
    writeln(znak, ' ', znaki[znak]);
end;
end.