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Delphi SysUtils.Supports 意外返回 true

转载 作者:行者123 更新时间:2023-12-03 15:24:46 26 4
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我正在根据Spring4d的文档示例制作一个eventPublisher

不同之处在于订阅者必须显式订阅事件。

我想根据他们是否触发他们的处理程序实现IEventHandler<TEventType>界面。

当发布传入事件时,我发现 IEventHandler<TEventType>使用事件的类名和 Spring4d 的 TType.FindType('IEventHandler<TEvent1>') 类型引用

然后,我循环遍历我的订阅者(实现 IEventHandler 接口(interface)的对象)并检查它是否支持 IEventHandler 类型。

问题是Supports方法返回true即使订阅者没有实现该接口(interface)。

此外,我尝试列出 TMyEventHandler2 的接口(interface)类型。它包含IEventHandler<TEvent2> ??

我相信这是由于 IEventHandler<TEvent2> 的限制造成的和IEventHandler<TEvent1>共享相同的 GUID

有解决办法吗?

使用这些类和接口(interface):

TEvent1 = class(TObject)
end;

TEvent2 = class(TObject)
end;

IEventHandler = interface(IInvokable)
[guid]
procedure Handle(aEvent : TObject);
end;

IEventHandler<T : class> = interface(IEventHandler)
[guid]
procedure Handle(aEvent : T);
end;

TMyEventHandler1 = class(TObject, IEventHandler, IEventHandler<TEvent1>)
public
procedure Handle(AEvent : TObject); overload;
procedure Handle(AEvent : TEvent1); overload;
end;

TMyEventHandler2 = class(TObject, IEventHandler, IEventHandler<TEvent2>)
public
procedure Handle(AEvent : TObject); overload;
procedure Handle(AEvent : TEvent2); overload;
end;

TEventPublisher = class(TObject)
public
fSubscribers : IList<TValue>;
procedure Subscribe(aSubscriber : TValue); // Simply adds the subscriber to the list of subscribers
procedure Publish(aEvent : TObject); // Publishes an event to the subscribers
end;

procedure TEventPublisher.Publish(const event: TObject; ownsObject: Boolean = True);
const
IEventSubscriberName = 'IEventSubscriber<*>';
var
consumerTypeName: string;
consumerType : TRttiType;
intfType : TRttiInterfaceType;
subscriber : TValue;
subscribed : IInterface;
lEventSubscriber: IEventSubscriber;
lIntfs : IReadOnlyList<TRttiInterfaceType>;
begin

consumerTypeName := StringReplace(IEventSubscriberName, '*', GetQualifiedClassName(event), []);
consumerType := TType.FindType(consumerTypeName);
intfType := consumerType as TRttiInterfaceType;

for subscriber in fSubscribers do
begin

lIntfs := TType.GetType(subscriber.AsObject.ClassInfo).GetInterfaces();

// lIntfs for TMyEventHandler2 containts IEventHandler<TEvent1> ???

if Supports(subscriber.AsObject, intfType.GUID, subscribed) then
if Supports(subscriber.AsObject, IEventSubscriber, lEventSubscriber) then
begin
intfType.GetMethod('Handle').Invoke(TValue.From(@subscribed, intfType.Handle), [event])
end;
end;

if ownsObject then
event.Free;
end;


lEventPublisher := TEventPublisher.Create;
lEventPublisher.Subscribe(TMyEventHandler1.Create);
lEventPublisher.Subscribe(TMyEventHandler2.Create);
lEventPublisher.Publish(TEvent1.Create); // Will both trigger TMyEventHandler1.Handle and TMyEventHandler2.Handle. Why ??

最佳答案

发生这种情况是因为,如果您将 guid 放在通用接口(interface)上,则该接口(interface)的每个特化都将具有相同的 guid,无论其通用类型参数如何。

我通常通过在界面中提供有关该信息的方法来解决此问题(例如 Spring.Collections.IEnumerable 有一个 ElementType 属性来获取 IEnumerable<T> 的实际类型)。

所以实现看起来像这样:

program GenericEventPublisher;

{$APPTYPE CONSOLE}

uses
Spring,
Spring.Collections,
System.SysUtils;

type
IEventHandler = interface
['{2E4BD8F4-4EB8-4B33-84F4-B70F42EF9208}']
procedure Handle(const event: TObject);
end;

IEventHandler<T: class> = interface
['{82B7521E-D719-4051-BE2C-2EC449A92B22}']
procedure Handle(const event: T);
function GetHandledClass: TClass;
end;

IEventPublisher = interface
['{2A460EF0-AE27-480F-ACEA-1B897F2DE056}']
procedure Subscribe(const subscriber: IEventHandler);
procedure Publish(const event: TObject; ownsObject: Boolean = True);
end;

TEventHandlerBase<T: class> = class(TInterfacedObject, IEventHandler, IEventHandler<T>)
private
function GetHandledClass: TClass;
procedure Handle(const event: TObject); overload;
public
procedure Handle(const event: T); overload; virtual; abstract;
end;

TEvent1 = class
end;

TEvent2 = class
end;

TMyEventHandler1 = class(TEventHandlerBase<TEvent1>)
public
procedure Handle(const event: TEvent1); override;
end;

TMyEventHandler2 = class(TEventHandlerBase<TEvent2>)
public
procedure Handle(const event: TEvent2); override;
end;

TEventPublisher = class(TInterfacedObject, IEventPublisher)
private
fSubscribers: IList<IEventHandler>;
public
constructor Create;
procedure Subscribe(const subscriber: IEventHandler);
procedure Publish(const event: TObject; ownsObject: Boolean = True);
end;

{ TEventPublisher }

constructor TEventPublisher.Create;
begin
fSubscribers := TCollections.CreateList<IEventHandler>;
end;

procedure TEventPublisher.Publish(const event: TObject; ownsObject: Boolean);
var
subscriber: IEventHandler;
eventSubscriber: IEventHandler<TObject>;
begin
for subscriber in fSubscribers do
if Supports(subscriber, IEventHandler<TObject>, eventSubscriber)
and (eventSubscriber.GetHandledClass = event.ClassType) then
eventSubscriber.Handle(event);

if ownsObject then
event.Free;
end;

procedure TEventPublisher.Subscribe(const subscriber: IEventHandler);
begin
fSubscribers.Add(subscriber)
end;

{ TEventHandlerBase<T> }

function TEventHandlerBase<T>.GetHandledClass: TClass;
begin
Result := T;
end;

procedure TEventHandlerBase<T>.Handle(const event: TObject);
begin
Assert(event is T);
Handle(T(event));
end;

{ TMyEventHandler1 }

procedure TMyEventHandler1.Handle(const event: TEvent1);
begin
Writeln(event.ClassName, ' handled by ', ClassName);
end;

{ TMyEventHandler2 }

procedure TMyEventHandler2.Handle(const event: TEvent2);
begin
Writeln(event.ClassName, ' handled by ', ClassName);
end;

var
eventPublisher: IEventPublisher;
begin
eventPublisher := TEventPublisher.Create;
eventPublisher.Subscribe(TMyEventHandler1.Create);
eventPublisher.Subscribe(TMyEventHandler2.Create);
eventPublisher.Publish(TEvent1.Create);
eventPublisher.Publish(TEvent2.Create);
end.

由于接口(interface)上存在类约束,我们可以确定接口(interface)是二进制兼容的,无论 T 的类型如何(因为它们只能是对象)。此外,使用通用事件处理程序的基类型可以减少需要编写的额外代码。它只是重定向非通用 Handle方法到通用方法必须在具体实现中实现。

此外,由于基类实现了这两个接口(interface),我们不需要将处理程序存储在 TValue 列表中但可以使用非通用接口(interface)类型并轻松访问它们,而不需要 RTTI。

现在是Publish方法是使用一个小技巧调用 SupportIEventHandler<TObject> - 自 eventSubscriber属于这种类型,我们可以传递 event参数为其 Handle方法恰好是正确的方法 - 这是因为我之前解释过的二进制兼容性,因为我们只是处理不同的类,因为 T 类型 - 如果我们没有该类约束,故事将完全不同。

关于Delphi SysUtils.Supports 意外返回 true,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49038991/

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