react-native - 如何覆盖功能组件中的导航选项？

Question

要使用类组件覆盖导航选项，它将类似于

export default class SomeClass extends Component {

    static navigationOptions = ({ navigation }) => {
        return {
            title: navigation.getParam('headerTitle'),
        }
    }

    componentDidMount() {
        this.props.navigation.setParams({ headerTitle: someVariableThatComesFromExternalCall })
    }

    ...
}

但是我如何使用功能组件来做到这一点？

export default function SomeFunctionalCompoenent({ navigation }) {

    // How and Where do I change the header title ?

    useEffect(() => { navigation.setParams({ headerTitle: someVariableThatComesFromExternalCall })})
    return (
        ...
    )
}

Answer 1

您仍然需要在功能组件上定义 navigationOptions。你这样做:

export default function SomeFunctionalComponent({ navigation }) {
    useEffect(() => { 
        navigation.setParams({ 
            headerTitle: someVariableThatComesFromExternalCall 
        }) 
    }, [])
}

SomeFunctionalComponent.navigationOptions = ({ navigation }) => {
    return {
        title: navigation.getParam('headerTitle'),
    }
}