django - 从Django Rest框架中的序列化器发送自定义错误响应？

Question

我想从序列化程序创建 View 发送自定义响应到我的应用程序的前端。我尝试了其余框架Response教程，但没有用。我的代码是:

class UserSerializer(serializers.ModelSerializer):
"""Serializer to serialize user model object"""

    class Meta:
        model = User
        fields = ('id', 'username', 'password', 'first_name', 'last_name')
        extra_kwargs = {'password': {'write_only': True}}

    def create(self, validated_data):
        """create a new user"""

        firstname = self.initial_data['first_name']
        lastname = self.initial_data['last_name']
        fullname = str(firstname) +" "+ str(lastname)
        email = self.initial_data['username'].lower()

        try:
           customer = User.create(
                name=fullname,
                email=email)

        except Error as e:
            error = {'message': e._message or 'Unknown error'}
            return Response(error,status=status.HTTP_400_BAD_REQUEST)

Answer 1

serializers.py

class UserSerializer(serializers.ModelSerializer):
"""Serializer to serialize user model object"""

    class Meta:
        model = User
        fields = ('id', 'username', 'password', 'first_name', 'last_name')
        extra_kwargs = {'password': {'write_only': True}}

    def create(self, validated_data):
        """create a new user"""

        firstname = validated_data['first_name']
        lastname = validated_data['last_name']
        fullname = str(firstname) +" "+ str(lastname)
        email = validated_data['username'].lower()

        try:
           customer = User.objects.create(
                name=fullname,
                email=email)
           return customer

        except Exception as e:
            error = {'message': ",".join(e.args) if len(e.args) > 0 else 'Unknown Error'}
            raise serializers.ValidationError(error)