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Firebase UI 电子邮件链接登录意图额外为空

转载 作者:行者123 更新时间:2023-12-03 14:48:26 25 4
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以下 3 个函数用于设置电子邮件和其他身份验证检查(按顺序调用)

    private void buildSignInIntentBuilder() {

ActionCodeSettings actionCodeSettings = ActionCodeSettings.newBuilder()
.setAndroidPackageName(getString(R.string.packageName), true, null)
.setHandleCodeInApp(true)
.setUrl(getString(R.string.dynamic_link_url))
.build();

List<AuthUI.IdpConfig> providers = Arrays.asList(
new AuthUI.IdpConfig.EmailBuilder()
.enableEmailLinkSignIn()
.setActionCodeSettings(actionCodeSettings)
.build(),
// new AuthUI.IdpConfig.EmailBuilder().setRequireName(false).build(),
new AuthUI.IdpConfig.PhoneBuilder()
.build(),
new AuthUI.IdpConfig.GoogleBuilder()
.build(),
new AuthUI.IdpConfig.FacebookBuilder()
.build());

signInIntentBuilder = AuthUI.getInstance()
.createSignInIntentBuilder()
.setIsSmartLockEnabled(false)
.setAvailableProviders(providers)
.setLogo(R.drawable.icon_forget_me_not_1);
}

private void catchEmailLinkSignIn() {
Log.d(TAG, "Intent: " + getIntent().getExtras());
if (AuthUI.canHandleIntent(getIntent())) {
if (getIntent().getExtras() == null) {
return;
}

String link = getIntent().getExtras().getString(ExtraConstants.EMAIL_LINK_SIGN_IN);
Log.d(TAG, "link: " + link);
if (link != null) {
signInIntentBuilder.setEmailLink(link);
}
}
}

private void createCheckAndSigninListener() {
// set firebase sign in listener
mAuthStateListner = firebaseAuth -> {
// Already logged in
FirebaseUser user = firebaseAuth.getCurrentUser();
if (user != null) {
Log.d(TAG, "user already signed in");
// Check user even if signed in to register him to database (if haven't)
FirebaseAuthHelper.getInstance().checkRegisterUser(user, this, CHECK_USER_DB);
} else {
Log.d(TAG, "user hasn't signed in");
// Signed out or hasn't logged in
startActivityForResult(
signInIntentBuilder
.build(),
RC_SIGN_IN
);

}
};
}

我已经与 Firebase 托管建立了动态​​链接。并且能够在单击收到的电子邮件链接后重定向到相同的事件。

然而,
String link = getIntent().getExtras().getString(ExtraConstants.EMAIL_LINK_SIGN_IN);
Log.d(TAG, "link: " + link); // --> produces "link: null"

显示尽管成功获得意图,但没有 EMAIL_LINK_SIGNIN额外在 getExtras() .我花了几个小时查看 FirebaseUi 的源代码,但我没有找到常量 EMAIL_LINK_SIGN_IN 的位置。使用以及如何解析动态链接的意图。

任何想法如何解决这个问题表示赞赏。我已经花了一整天的时间试图弄清楚这一点。

最佳答案

而不是使用 String link = getIntent().getExtras().getString(ExtraConstants.EMAIL_LINK_SIGN_IN);
使用 getIntent().getData().toString();反而。

关于Firebase UI 电子邮件链接登录意图额外为空,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58350107/

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