Delphi:简单的字符串加密

Question

我有一个字符串 - 主板的序列号(只有数字和字母)。如何加密/解密并获得正常 View :仅从 A 到 Z 的字母和从 0 到 9 的数字。用户必须向我发送字符串，我必须回复。

我可以加密，但字符不可读。

谢谢!

Answer 1

支持 Unicode 的简单 Enc/Dec，Enc 输出仅是十六进制字符:

const CKEY1 = 53761;
      CKEY2 = 32618;

function EncryptStr(const S :WideString; Key: Word): String;
var   i          :Integer;
      RStr       :RawByteString;
      RStrB      :TBytes Absolute RStr;
begin
  Result:= '';
  RStr:= UTF8Encode(S);
  for i := 0 to Length(RStr)-1 do begin
    RStrB[i] := RStrB[i] xor (Key shr 8);
    Key := (RStrB[i] + Key) * CKEY1 + CKEY2;
  end;
  for i := 0 to Length(RStr)-1 do begin
    Result:= Result + IntToHex(RStrB[i], 2);
  end;
end;

function DecryptStr(const S: String; Key: Word): String;
var   i, tmpKey  :Integer;
      RStr       :RawByteString;
      RStrB      :TBytes Absolute RStr;
      tmpStr     :string;
begin
  tmpStr:= UpperCase(S);
  SetLength(RStr, Length(tmpStr) div 2);
  i:= 1;
  try
    while (i < Length(tmpStr)) do begin
      RStrB[i div 2]:= StrToInt('$' + tmpStr[i] + tmpStr[i+1]);
      Inc(i, 2);
    end;
  except
    Result:= '';
    Exit;
  end;
  for i := 0 to Length(RStr)-1 do begin
    tmpKey:= RStrB[i];
    RStrB[i] := RStrB[i] xor (Key shr 8);
    Key := (tmpKey + Key) * CKEY1 + CKEY2;
  end;
  Result:= UTF8Decode(RStr);
end;

示例:

procedure TForm1.btn1Click(Sender: TObject);
begin
  txt2.Text:= EncryptStr(txt1.Text, 223);
  lbl1.Caption:= DecryptStr(txt2.Text, 223);
end;