unit-testing - 如何使用 MOQ 框架为抽象基类创建 Mock？

Question

我想为 MyClass 编写单元测试，但它的基类是一个抽象类。

public class MyClass : AbstractBaseClass
{
}

我想模拟 AbstractBase 类，以便在创建要测试的 MyClass 实例时跳过其构造函数中的一些逻辑。无论如何我可以做到这一点吗？

//Unit Test
var test = new Mock<IInterface>();
var derivedclass = new DerivedClass(test.Object);

test.Setup(d=>d.MyMethod(It.IsAny<string>()).returns(2);
derivedclass.MyMethod("hello");


// Derived Class
class DerivedClass : AbstractClass{

     //constuctor
    public DerivedClass(IInterface interface){
        _interface = interface;
    }
    public MyMethod(string str){
        return 2;
    }
}

//Abstract Class
public abstract class AbstractClass
{

 // This method gets called when i create the  instance of the derived class in my unit   
  test..

   protected AbstractedClass() : this(new SomeOtherClass()){
       DoSomethingElse();    /// I want to skip this method or mock it.
   }
 }

Answer 1

是的，这是 Moq 中一个非常基本的场景。
假设您的抽象类如下所示:

public class MyClass : AbstractBaseClass
{
    public override int Foo()
    {
        return 1;
    }
}

您可以编写以下测试:

[Test]
public void MoqTest()
{
    var mock = new Moq.Mock<AbstractBaseClass>();            
    // set the behavior of mocked methods
    mock.Setup(abs => abs.Foo()).Returns(5);

    // getting an instance of the class
    var abstractBaseClass = mock.Object;
    // Asseting it actually works :)
    Assert.AreEqual(5, abstractBaseClass.Foo());
}