R:将多个 bool 列折叠为单个属性列，每个组合都有新行

Question

这个问题在这里已经有了答案:





Converting multiple boolean columns to single factor column

(4 个回答)


2年前关闭。




尝试将具有多个 bool 列的数据框融合或折叠到具有 id 列和折叠值列的两列数据库中，但每个值都会产生一个新行。

示例开头:

      A S1 S2 S3 S4
1   ex1  1  0  0  0
2   ex2  0  1  0  0
3   ex3  0  0  1  0
4   ex4  1  1  0  0
5   ex5  0  1  0  1
6   ex6  0  1  0  0
7   ex7  1  1  1  0
8   ex8  0  1  1  0
9   ex9  0  0  1  0
10 ex10  1  0  0  0

期望的输出:

A   Type
ex1 S1
ex2 S2
ex3 S3
ex4 S1
ex4 S2
ex5 S2
ex5 S4
ex6 S2
ex7 S1
ex7 S2
ex7 S3
ex8 S2
ex8 S3
ex9 S3
ex10 S1

提前致谢!

Answer 1

在基础 R 中:

 subset(cbind(A=dat[,1],stack(dat[-1])),values==1,-2)
      A ind
1   ex1  S1
4   ex4  S1
7   ex7  S1
10 ex10  S1
12  ex2  S2
14  ex4  S2
15  ex5  S2
16  ex6  S2
17  ex7  S2
18  ex8  S2
23  ex3  S3
27  ex7  S3
28  ex8  S3
29  ex9  S3
35  ex5  S4

在 tidyverse 中:

library(tidyverse)
dat%>%
   gather(Type,j,-A)%>%
   filter(j==1)%>%
   select(-j)
      A Type
1   ex1   S1
2   ex4   S1
3   ex7   S1
4  ex10   S1
5   ex2   S2
6   ex4   S2
7   ex5   S2
8   ex6   S2
9   ex7   S2
10  ex8   S2
11  ex3   S3
12  ex7   S3
13  ex8   S3
14  ex9   S3
15  ex5   S4