Graphviz 节点的点垂直对齐

Question

我得到了这个点图，并希望节点 A 和 D、B 和 E 以及 C 和 F 对齐。这是相关的点代码:

digraph{

A
B
C
D
E
F

{rank = same; B; C}
{rank = same; E; F}

A -> B [label="2", weight=2]
A -> C [label="0", style=dashed, weight=2]
B -> C [label="0", style=dashed, weight=2]
B -> D [label="2", style=dashed, weight=2]
C -> D [label="0", weight=2]
D -> E [label="1", style=dashed, weight=2]
D -> F [label="0", weight=2]
E -> F [label="0", weight=2]
F -> A
}

如您所见，我已经尝试将权重应用于边缘，但没有成功

Answer 1

可以使用 group节点的属性，建议将同一组的节点之间的边沿直线对齐。
使用 group 属性声明节点:

A [group=g1]
{rank = same; B[group=g2]; C[group=g3]}
D [group=g1]
{rank = same; E[group=g2]; F[group=g3]}

然后确保所有这些节点之间都有(不可见的)边:

edge[style=invis];
A -> D
B -> E
C -> F

一切都在一起:

digraph G {
  A [group=g1]
  {rank = same; B[group=g2]; C[group=g3]}
  D [group=g1]
  {rank = same; E[group=g2]; F[group=g3]}

  A -> B [label="2", weight=2]
  A -> C [label="0", style=dashed, weight=2]
  B -> C [label="0", style=dashed, weight=2]
  B -> D [label="2", style=dashed, weight=2]
  C -> D [label="0", weight=2]
  D -> E [label="1", style=dashed, weight=2]
  D -> F [label="0", weight=2]
  E -> F [label="0", weight=2]
  F -> A

  edge[style=invis];
  A -> D
  B -> E
  C -> F
}