gpt4 book ai didi

scala - 从 Java 属性获取 Scala 映射

转载 作者:行者123 更新时间:2023-12-03 14:34:19 26 4
gpt4 key购买 nike

我试图使用 java Iterators 和/或 Enumerations 将环境变量拉入 scala 脚本,并意识到 Frankenstein 博士可能声称出身,所以我从丑陋的树中修改了以下内容:

import java.util.Map.Entry
import System._

val propSet = getProperties().entrySet().toArray()
val props = (0 until propSet.size).foldLeft(Map[String, String]()){(m, i) =>
val e = propSet(i).asInstanceOf[Entry[String, String]]
m + (e.getKey() -> e.getValue())
}

例如打印上述相同的环境
props.keySet.toList.sortWith(_ < _).foreach{k =>
println(k+(" " * (30 - k.length))+" = "+props(k))
}

拜托,请不要着手完善这个 t$#d,只需向我展示我确信在这种情况下存在的 scala gem(即 java 属性 --> scala.Map),提前致谢;@)

最佳答案

斯卡拉 2.10.3

import scala.collection.JavaConverters._

//Create a variable to store the properties in
val props = new Properties

//Open a file stream to read the file
val fileStream = new FileInputStream(new File(fileName))
props.load(fileStream)
fileStream.close()

//Print the contents of the properties file as a map
println(props.asScala.toMap)

关于scala - 从 Java 属性获取 Scala 映射,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2016268/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com