sql - 如何在sql中选择连续日期

Question

是否有任何功能可以检查连续日期。我在处理以下问题时遇到问题:

我的 table 上有一个 datetime具有以下数据的列:

----------
2015-03-11
2015-03-12
2015-03-13
2015-03-16

给定开始日期为 2015-3-11和结束日期为 2015-3-17 .我希望结果为:

----------
2015-03-11
2015-03-12
2015-03-13

任何人都可以提出任何建议吗？

Answer 1

我认为这是 的变体Grouping Islands of Contiguous Dates 问题。这可以使用 ROW_NUMBER() 来完成:

SQL Fiddle

CREATE TABLE Test(
    tDate   DATETIME
)
INSERT INTO Test VALUES
('20150311'), ('20150312'), ('20150313'), ('20150316');

DECLARE @startDate  DATE = '20150311'
DECLARE @endDate    DATE = '20150317'

;WITH Cte AS(
    SELECT
        *,
        RN = DATEADD(DD, - (ROW_NUMBER() OVER(ORDER BY tDATE) - 1), tDate)
    FROM Test
    WHERE 
        tDate >= @startDate
        AND tDate < DATEADD(DAY, 1, @endDate)
)
SELECT CAST(tDate AS DATE)
FROM CTE
WHERE RN = @startDate

结果

|------------|
| 2015-03-11 |
| 2015-03-12 |
| 2015-03-13 |

这是 SQL Server 2005 版本:

SQL Fiddle

DECLARE @startDate  DATETIME
DECLARE @endDate    DATETIME

SET @startDate  = '20150311'
SET @endDate    = '20150317'

;WITH Cte AS(
    SELECT
        *,
        RN = DATEADD(DD, -(ROW_NUMBER() OVER(ORDER BY tDATE)-1), tDate)
    FROM Test
    WHERE 
        tDate >= @startDate
        AND tDate < DATEADD(DAY, 1, @endDate)
)
SELECT CONVERT(VARCHAR(10), tDate, 121)
FROM CTE
WHERE RN = @startDate