gpt4 book ai didi

C# 在控制台中显示二叉搜索树

转载 作者:行者123 更新时间:2023-12-03 13:44:07 25 4
gpt4 key购买 nike

我有简单的二叉搜索树

public class BNode
{
public int item;
public BNode right;
public BNode left;

public BNode(int item)
{
this.item = item;
}
}

public class BTree
{
private BNode _root;
private int _count;
private IComparer<int> _comparer = Comparer<int>.Default;


public BTree()
{
_root = null;
_count = 0;
}


public bool Add(int Item)
{
if (_root == null)
{
_root = new BNode(Item);
_count++;
return true;
}
else
{
return Add_Sub(_root, Item);
}
}

private bool Add_Sub(BNode Node, int Item)
{
if (_comparer.Compare(Node.item, Item) < 0)
{
if (Node.right == null)
{
Node.right = new BNode(Item);
_count++;
return true;
}
else
{
return Add_Sub(Node.right, Item);
}
}
else if (_comparer.Compare(Node.item, Item) > 0)
{
if (Node.left == null)
{
Node.left = new BNode(Item);
_count++;
return true;
}
else
{
return Add_Sub(Node.left, Item);
}
}
else
{
return false;
}
}

public void Print()
{
Print(_root, 4);
}

public void Print(BNode p, int padding)
{
if (p != null)
{
if (p.right != null)
{
Print(p.right, padding + 4);
}
if (padding > 0)
{
Console.Write(" ".PadLeft(padding));
}
if (p.right != null)
{
Console.Write("/\n");
Console.Write(" ".PadLeft(padding));
}
Console.Write(p.item.ToString() + "\n ");
if (p.left != null)
{
Console.Write(" ".PadLeft(padding) + "\\\n");
Print(p.left, padding + 4);
}
}
}
}

我可以在其中插入值,例如
BTree btr = new BTree();
btr.Add(6);
btr.Add(2);
btr.Add(3);
btr.Add(11);
btr.Add(30);
btr.Add(9);
btr.Add(13);
btr.Add(18);

我想在我的控制台应用程序中显示我的树。我有一个 btr.Print();从左到右显示我的树( 6 是根) - 但我对它不满意。

enter image description here

问题 :有没有更好的方法在控制台应用程序中显示这棵树?甚至对此的改进 Print()会帮助我。

最佳答案

我已经结束了以下方法,允许您打印任意子树:

public static class BTreePrinter
{
class NodeInfo
{
public BNode Node;
public string Text;
public int StartPos;
public int Size { get { return Text.Length; } }
public int EndPos { get { return StartPos + Size; } set { StartPos = value - Size; } }
public NodeInfo Parent, Left, Right;
}

public static void Print(this BNode root, string textFormat = "0", int spacing = 1, int topMargin = 2, int leftMargin = 2)
{
if (root == null) return;
int rootTop = Console.CursorTop + topMargin;
var last = new List<NodeInfo>();
var next = root;
for (int level = 0; next != null; level++)
{
var item = new NodeInfo { Node = next, Text = next.item.ToString(textFormat) };
if (level < last.Count)
{
item.StartPos = last[level].EndPos + spacing;
last[level] = item;
}
else
{
item.StartPos = leftMargin;
last.Add(item);
}
if (level > 0)
{
item.Parent = last[level - 1];
if (next == item.Parent.Node.left)
{
item.Parent.Left = item;
item.EndPos = Math.Max(item.EndPos, item.Parent.StartPos - 1);
}
else
{
item.Parent.Right = item;
item.StartPos = Math.Max(item.StartPos, item.Parent.EndPos + 1);
}
}
next = next.left ?? next.right;
for (; next == null; item = item.Parent)
{
int top = rootTop + 2 * level;
Print(item.Text, top, item.StartPos);
if (item.Left != null)
{
Print("/", top + 1, item.Left.EndPos);
Print("_", top, item.Left.EndPos + 1, item.StartPos);
}
if (item.Right != null)
{
Print("_", top, item.EndPos, item.Right.StartPos - 1);
Print("\\", top + 1, item.Right.StartPos - 1);
}
if (--level < 0) break;
if (item == item.Parent.Left)
{
item.Parent.StartPos = item.EndPos + 1;
next = item.Parent.Node.right;
}
else
{
if (item.Parent.Left == null)
item.Parent.EndPos = item.StartPos - 1;
else
item.Parent.StartPos += (item.StartPos - 1 - item.Parent.EndPos) / 2;
}
}
}
Console.SetCursorPosition(0, rootTop + 2 * last.Count - 1);
}

private static void Print(string s, int top, int left, int right = -1)
{
Console.SetCursorPosition(left, top);
if (right < 0) right = left + s.Length;
while (Console.CursorLeft < right) Console.Write(s);
}
}

如您所见,我添加了一些影响格式的参数。默认情况下,它产生最紧凑的表示。

为了玩起来,我修改了 BTree类如下:
public class BTree
{
// ...

public BNode Root { get { return _root; } }

public void Print()
{
Root.Print();
}
}

使用您的示例数据,以下是一些结果:
btr.Root.Print();
enter image description here
btr.Root.Print(textFormat: "(0)", spacing: 2);
enter image description here

更新: IMO 上面的默认格式是紧凑且可读的,但只是为了好玩,调整了算法以产生更多的“图形”输出(删除了 textFormatspacing 参数):
public static class BTreePrinter
{
class NodeInfo
{
public BNode Node;
public string Text;
public int StartPos;
public int Size { get { return Text.Length; } }
public int EndPos { get { return StartPos + Size; } set { StartPos = value - Size; } }
public NodeInfo Parent, Left, Right;
}

public static void Print(this BNode root, int topMargin = 2, int leftMargin = 2)
{
if (root == null) return;
int rootTop = Console.CursorTop + topMargin;
var last = new List<NodeInfo>();
var next = root;
for (int level = 0; next != null; level++)
{
var item = new NodeInfo { Node = next, Text = next.item.ToString(" 0 ") };
if (level < last.Count)
{
item.StartPos = last[level].EndPos + 1;
last[level] = item;
}
else
{
item.StartPos = leftMargin;
last.Add(item);
}
if (level > 0)
{
item.Parent = last[level - 1];
if (next == item.Parent.Node.left)
{
item.Parent.Left = item;
item.EndPos = Math.Max(item.EndPos, item.Parent.StartPos);
}
else
{
item.Parent.Right = item;
item.StartPos = Math.Max(item.StartPos, item.Parent.EndPos);
}
}
next = next.left ?? next.right;
for (; next == null; item = item.Parent)
{
Print(item, rootTop + 2 * level);
if (--level < 0) break;
if (item == item.Parent.Left)
{
item.Parent.StartPos = item.EndPos;
next = item.Parent.Node.right;
}
else
{
if (item.Parent.Left == null)
item.Parent.EndPos = item.StartPos;
else
item.Parent.StartPos += (item.StartPos - item.Parent.EndPos) / 2;
}
}
}
Console.SetCursorPosition(0, rootTop + 2 * last.Count - 1);
}

private static void Print(NodeInfo item, int top)
{
SwapColors();
Print(item.Text, top, item.StartPos);
SwapColors();
if (item.Left != null)
PrintLink(top + 1, "┌", "┘", item.Left.StartPos + item.Left.Size / 2, item.StartPos);
if (item.Right != null)
PrintLink(top + 1, "└", "┐", item.EndPos - 1, item.Right.StartPos + item.Right.Size / 2);
}

private static void PrintLink(int top, string start, string end, int startPos, int endPos)
{
Print(start, top, startPos);
Print("─", top, startPos + 1, endPos);
Print(end, top, endPos);
}

private static void Print(string s, int top, int left, int right = -1)
{
Console.SetCursorPosition(left, top);
if (right < 0) right = left + s.Length;
while (Console.CursorLeft < right) Console.Write(s);
}

private static void SwapColors()
{
var color = Console.ForegroundColor;
Console.ForegroundColor = Console.BackgroundColor;
Console.BackgroundColor = color;
}
}

结果是:

enter image description here

关于C# 在控制台中显示二叉搜索树,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36311991/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com