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Flutter FormatException : Unexpected character (at character 1)

转载 作者:行者123 更新时间:2023-12-03 13:30:58 41 4
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在 flutter 中,我使用了一个php文件,该文件从数据库查询返回json响应,但是当我尝试解码json时,出现此错误:

E/flutter ( 8294): [ERROR:flutter/lib/ui/ui_dart_state.cc(148)] Unhandled
Exception: FormatException: Unexpected character (at character 1)
E/flutter ( 8294): [{"0":"PRUEBA","usu_nombre":"PRUEBA"}]
E/flutter ( 8294): ^

这是我的飞镖功能:
Future<String> iniciarSesion() async{
var usuario = textUsuario.text;
var password = textPassword.text;
var nombreUsuario;
var url ="http://192.168.1.37/usuario.php";

//Metodo post
var response = await http.post(
url,
headers:{ "Accept": "application/json" } ,
body: { "usuario": '$usuario',"password": '$password'},
encoding: Encoding.getByName("utf-8")
);
List data = json.decode(response.body);
}

以及来自我的php文件的代码:
<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');

include_once "Clases/conexion.php";

$usuario = $_POST['usuario'];
$password = $_POST['password'];

$consulta = "select usu_nombre
FROM usu_usuarios
WHERE usu_nusuario='$usuario'and usu_password='$password' and usu_activo='SI'";

$mysql_obj = new Conectar();
$mysqli = $mysql_obj->crearConexion();

if($result = $mysqli->query($consulta)) {
if ($mysqli->affected_rows > 0) {
while($row = $result->fetch_array()) {
$myArray[] = $row;
}
header('Content-type: application/json');
echo json_encode($myArray);
}else {
header("HTTP/1.0 401 Datos Incorrectos");
header('Content-type: application/json');
$data = array("mensaje" => "Datos Incorrectos");
echo json_encode($data);
}}
?>

我正在使用http dart依赖

最佳答案

最后,我使用laravel解决了问题,以这种方式返回了数据

return response()->json($yourData, 200, ['Content-Type' => 'application/json;charset=UTF-8', 'Charset' => 'utf-8'],
JSON_UNESCAPED_UNICODE

我注意到,此错误仅发生在模拟器中,而不发生在物理设备中。

关于Flutter FormatException : Unexpected character (at character 1),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55671441/

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