reactjs - react : Children onclick to change parent's state for re-rendering

Question

我对 React 还很陌生。我试图让家长根据州更改显示的页面。我的子组件中有一个按钮，它应该向父组件发送“true”或“false”，以便它知道是否渲染它。我认为应该用这样的 Prop 来完成:

this.state = {
   btnNewScreen: this.props.btnNewScreen //true or false
};

但我无法让它发挥作用。你能给一些建议吗？这是完整的父-子

父级 - maindisplay.js

import React from 'react';
import Mainpage_Addscreen from '../components/subcomponents/mainpage-addscreen';
import Mainpage_Showscreens from '../components/subcomponents/mainpage-showscreens';
//
class MainDisplay extends React.Component {
    constructor() {
        super();
        this.state = {
            btnNewScreen: false //should be this.props.btnNewScreen?
        };
    }

    render() {
        var renderThis;
        if (!this.state.btnNewScreen) {
            renderThis =
                <div>
                    <Mainpage_Addscreen />
                    <Mainpage_Showscreens />
                </div>
        }
        else {
            //renderThis = <AddScreen />
            renderThis =
                <div>
                    <Mainpage_Addscreen />
                    <h3>Change to this when true (button click)</h3>
                </div>
        }
        return (
            <div>
                {renderThis}
            </div>
        );
      }
    }


    export default MainDisplay;

子-mainpage-addscreen.js

import React from 'react';

import Glyphicon from 'react-bootstrap/lib/Glyphicon';
import Button from 'react-bootstrap/lib/Button';

class Mainpage_Addscreen extends React.Component {
    constructor() {
        super();
        this.state = {
            btnNewScreen: true
        };
        this.newScreen = this.newScreen.bind(this);
    }

    newScreen(e) {
        this.setState({ btnNewScreen: !this.state.btnNewScreen });
        console.log(this.state.btnNewScreen);
    }
    render() {
        var text = this.state.btnNewScreen ? 'Add new' : 'Screens';
        return (
            <div className="main_window col-sm-offset-1 col-sm-10">
                <h3 id="addscreens">Screens: </h3>
                <Button id="addScreen" className="btn btn-primary dropdown-toggle" type="button" data-toggle="dropdown" onClick={this.newScreen}><Glyphicon id="refresh_screens" glyph="plus" />&nbsp; {text}</Button>
            </div>
        );
    }
}


export default Mainpage_Addscreen;

Answer 1

您需要做的是将一个方法从父级传递给子级，该方法可以在单击按钮时调用。这个属于父级的方法将改变状态。
在 MainPage.js 中

changeButtonState(event) {
    this.setState({btnNewScreen: !this.state.btnNewScreen})
}

将此方法传递给您的子组件

<Mainpage_Addscreen buttonClick={this.changeButtonState.bind(this)} />

最后在子组件中，

<Button ....   onClick={this.props.buttonClick} />