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reactjs - React Formik - 仅在表单提交时触发验证

转载 作者:行者123 更新时间:2023-12-03 13:18:15 24 4
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我在我的 React Native 应用程序中使用 Formik。在登录表单上,我有两个字段:电子邮件和密码,这两个字段都是必需的。

我写了这样的验证规则:

export const LoginSchema = Yup.object().shape({
email: Yup.string()
.email('The email is invalid')
.required('This field is required'),
password: Yup.string()
.min(6, 'The password is too short')
.max(12, 'The password is too long')
.required('This field is required'),
});

我只需要在表单提交时触发验证并显示错误弹出窗口。我已阅读文档,但找不到解决方案,因为验证会触发 onBlur。如何做到这一点?

谢谢!

const Login = ({ navigation }) => {
const [isLoading, setIsLoading] = useState(true);
const [isVisible, setIsVisible] = useState(false);

useEffect(() => {
// Later check for token
const tokenIsStored = true;

if (tokenIsStored) {
setIsLoading(false);
}
});

const onLogin = values => {
console.log(values, 'on login');

// Pass value to BE endpoint
navigation.navigate('Dashboard');
};

const onModalClose = () => {
setIsVisible(false);
};

console.log(isVisible);

if (!isLoading) {
return (
<ScrollContainer keyboardShouldPersistTaps="handled">
<ThemedStatusBar />

<ThemedModal
isVisible={isVisible}
primaryMessage="Log In Failed"
secondaryMessage="Please check your password"
btnTitle="OK"
btnPress={() => onModalClose()}
/>

<Formik
initialValues={{ email: '', password: '' }}
validationSchema={LoginSchema}
onSubmit={values => onLogin(values)}
>
{props => (
<View>
<ScrollContainer BackgroundColor={Colors.greyColor} Padding="0px" style={styles.loginForm}>
<ThemedInput
onChangeText={props.handleChange('email')}
onBlur={props.handleBlur('email')}
value={props.values.email}
placeholder="Email"
keyboardType="email-address"
/>
<ThemedInput
onChangeText={props.handleChange('password')}
onBlur={props.handleBlur('password')}
value={props.values.password}
placeholder="Password"
overrideStyles={styles.loginInputBottom}
secureTextEntry
/>
{props.errors.email && setIsVisible(true)}
</ScrollContainer>
<ThemedButton onPress={props.handleSubmit} title="Log In" />
</View>
)}
</Formik>
</ScrollContainer>
);
}
return <ThemedLoader isLoading />;
};

export default Login;

最佳答案

根据docs

You can control when Formik runs validation by changing the values of <Formik validateOnChange> and/or <Formik validateOnBlur> props depending on your needs.

传递给您的Formik Prop validateOnChange={false}validateOnBlur={false}

关于reactjs - React Formik - 仅在表单提交时触发验证,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56742376/

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