javascript - 跳过 JavaScript 函数中的参数

Question

我有这样的功能:

function foo(a, b, c, d, e, f) {
}

为了仅使用 f 调用此函数争论，我知道我应该这样做:

foo(undefined, undefined, undefined, undefined, undefined, theFValue);

有没有更简洁的方法来做到这一点？

解决方案 :
我选择了一些建议的解决方案(不使用辅助第三功能)

// zero - ideal one, actually not possible(?!)
foo(f: fValue);

// one - asks a "strange" declaration
var _ = undefined;
foo(_, _, _, _, _, fValue);

// two - asks the {} to be used instead of a 'natural' list of args
//     - users should be aware about the internal structure of args obj
//       so this option is not 'intellisense friendly'
function foo(args){
    // do stuff with `args.a`, `args.b`, etc.
}    
foo({f: fValue});

Answer 1

这样的:

foo(undefined, undefined, undefined, undefined, undefined, arg1, arg2);

. 等于:

foo(...Array(5), arg1, arg2);

。或者:

foo(...[,,,,,], arg1, arg2);

这样的:

foo(undefined, arg1, arg2);

. 等于:

foo(...Array(1), arg1, arg2);

。或者:

foo(...[,], arg1, arg2);

这样的:

foo(arg1, arg2);

. 等于:

foo(...Array(0), arg1, arg2);

。或者:

foo(...[], arg1, arg2);