react-native - 如何检测react-native中的首次启动

Question

检测 react-native 应用程序的首次和初始启动以显示登录/介绍屏幕的好方法是什么？

Answer 1

你的逻辑应该遵循这个:

class MyStartingComponent extends React.Component {
    constructor(){
        super();
        this.state = {firstLaunch: null};
    }
    componentDidMount(){
        AsyncStorage.getItem("alreadyLaunched").then(value => {
            if(value == null){
                 AsyncStorage.setItem('alreadyLaunched', true); // No need to wait for `setItem` to finish, although you might want to handle errors
                 this.setState({firstLaunch: true});
            }
            else{
                 this.setState({firstLaunch: false});
            }}) // Add some error handling, also you can simply do this.setState({fistLaunch: value == null})
    }
    render(){
       if(this.state.firstLaunch === null){
           return null; // This is the 'tricky' part: The query to AsyncStorage is not finished, but we have to present something to the user. Null will just render nothing, so you can also put a placeholder of some sort, but effectively the interval between the first mount and AsyncStorage retrieving your data won't be noticeable to the user.
       }else if(this.state.firstLaunch == true){
           return <FirstLaunchComponent/>
       }else{
           return <NotFirstLaunchComponent/>
       }
}

希望能帮助到你