multithreading - OS X libstdc++可以防止boost::thread中断？

Question

考虑以下示例代码，该示例代码创建一个线程并使用thread::interrupt调用从主线程中中断该线程:

#include <iostream>
#include <boost/thread.hpp>
#include <boost/chrono.hpp>
#include <boost/ref.hpp>

int main()
{
    boost::thread t([]{
        int counter = 0;

        while (1){
            std::cout << "interruption enabled " << boost::this_thread::interruption_enabled() << std::endl;
            try {
                counter++;

                if (counter % 5 == 0)
                    throw std::runtime_error("runtime error!");

                std::cout << "thread function\n";
                boost::this_thread::sleep_for(boost::chrono::milliseconds(300));
            }
            catch (boost::thread_interrupted &interruption)
            {
                std::cout << "oops!.. time to finish!" << std::endl;
                return;
                //std::cout << "...but couldn't o_O..." << std::endl;
            }
            catch (std::exception &e)
            {
                std::cout << "some exception: " << e.what() << std::endl;
            }
        }
    });

    boost::this_thread::sleep_for(boost::chrono::milliseconds(3000));
    t.interrupt();
    std::cout << "joinable: " << t.joinable() << std::endl;
    if (t.joinable())
        if (!t.try_join_for(boost::chrono::milliseconds(500)))
        {
            std::cout <<"still RUNNING\n detach it..." << std::endl;
            t.detach();
        }

    std::cout << "main thread\n";
    boost::this_thread::sleep_for(boost::chrono::milliseconds(500));

    return 0;
}

现在，当像这样在OS X 10.10.3上编译时(默认使用libc++):
g++ main.cpp -I<path_to_boost_1_54_0> -std=gnu++11 -lboost_thread-mt -lboost_system-mt -lboost_chrono-mt -L<path_to_boost_1_54_0>/stage/lib
输出显示启用了中断:

interruption enabled 1
thread function
interruption enabled 1
thread function
...

但是，如果使用libstdc++:
g++ main.cpp -I<path_to_boost_1_54_0> -std=gnu++11 -stdlib=libstdc++ -lboost_thread-mt -lboost_system-mt -lboost_chrono-mt -L<path_to_boost_1_54_0>/stage/lib
我得到的输出告诉我禁用了中断:

interruption enabled 0
thread function
interruption enabled 0
thread function
...

有这种行为的原因吗？我使用了boost v1.54.0和此LLVM v6.1.0:

$ g++ -v
Configured with: --prefix=/Applications/Xcode.app/Contents/Developer/usr --with-gxx-include-dir=/usr/include/c++/4.2.1
Apple LLVM version 6.1.0 (clang-602.0.49) (based on LLVM 3.6.0svn)
Target: x86_64-apple-darwin14.3.0
Thread model: posix

谢谢

Answer 1

我已经在linux上复制了它:

带有gcc 4.8、4.9的

，它可以工作

带有tlang 3.5和libstdc++的

interruption enabled 1
thread function
interruption enabled 1
thread function
interruption enabled 1
thread function
interruption enabled 1
thread function
interruption enabled 1
some exception: runtime error!
interruption enabled 1
thread function
interruption enabled 1
thread function
interruption enabled 1
thread function
interruption enabled 1
thread function
interruption enabled 1
some exception: runtime error!
interruption enabled 1
thread function
interruption enabled 1
thread function
joinable: 1
oops!.. time to finish!
main thread

带clang 3.5和libc++的

不起作用:

interruption enabled 128
thread function
oops!.. time to finish!
joinable: 1
Segmentation fault (core dumped)

我认为，应该在 boost 列表中报告此问题。

Boost开发人员可能会指出这是libc++中的错误