python - 有人可以帮我理解这个简短的 .py

Question

我试图理解 python 中的基本线程，我无法理解池如何与队列模块一起工作。下面是我正在阅读的操作指南中使用的示例服务器:http://www.devshed.com/c/a/Python/Basic-Threading-in-Python/2/ .基本上我不明白的是变量pickledList如何最终可用于线程范围以发送给客户端，因为它从未在代码中的任何地方传递给线程

import pickle
import Queue
import socket
import threading

# We'll pickle a list of numbers, yet again:
someList = [ 1, 2, 7, 9, 0 ]
pickledList = pickle.dumps ( someList )

# A revised version of our thread class:
class ClientThread ( threading.Thread ):

   # Note that we do not override Thread's __init__ method.
   # The Queue module makes this not necessary.

   def run ( self ):

      # Have our thread serve "forever":
      while True:

         # Get a client out of the queue
         client = clientPool.get()

         # Check if we actually have an actual client in the client variable:
         if client != None:

            print 'Received connection:', client [ 1 ] [ 0 ]
            client [ 0 ].send ( pickledList )
            for x in xrange ( 10 ):
               print client [ 0 ].recv ( 1024 )
            client [ 0 ].close()
            print 'Closed connection:', client [ 1 ] [ 0 ]

# Create our Queue:
clientPool = Queue.Queue ( 0 )

# Start two threads:
for x in xrange ( 2 ):
   ClientThread().start()

# Set up the server:
server = socket.socket ( socket.AF_INET, socket.SOCK_STREAM )
server.bind ( ( '', 2727 ) )
server.listen ( 5 )

# Have the server serve "forever":
while True:
   clientPool.put ( server.accept() )

Answer 1

pickledList变量可用作 ClientThread 中的全局变量类(class)。见 Short Description of Python Scoping Rules .