python-3.x - 如何确保 tkinter 中不跳过 "bind"顺序？

Question

我正在尝试使用 tkinter 创建一个游戏，其中玩家将他们的名字输入到一个条目小部件中。

输入他们的名字后，用户应该按下回车键来调用函数“player_names”，这将理想情况下将玩家名字保存在一个列表中，删除条目小部件中的文本，然后继续下一个循环(即玩家)。

该脚本似乎忽略了绑定(bind)并直接移动到“self.name_entry.destroy()”行。如何确保脚本在继续之前等待命令？

def initialise_game(self, num_of_players):

    self.players_list = []
    for i in range(num_of_players):
        player_num = i+1
        self.name_label = tk.Label(self.bg_label, text='What is the name'
                                   ' of Player ' + str(player_num) + '?')
        self.name_label.grid(row=0, padx=200, pady=120)

        self.name_entry = tk.Entry(self.bg_label)
        self.name_entry.grid(row=1, padx=200, pady=0)
        self.name_entry.bind('<Return>', self.player_names)

    self.name_entry.destroy()


def player_names(self, event):
    self.players_list.append(self.name_entry.get())
    self.name_entry.delete(0, 'end')

Answer 1

Entry不像 input()它不会停止代码并等到您输入文本并按 Enter 键。 GUI创建 Entry它在 Entry 之后执行代码立刻。你有 bind分配将在您按 Enter 时执行的函数，该函数应从 Entry 中获取值，并替换小部件(或仅标签中的文本)。它还应该删除 Entry在最后一个玩家之后，所以你必须计算函数执行了多少次(或者你已经有多少玩家 - self.player_num)

我没有测试这段代码，但它应该可以工作。

def initialise_game(self, num_of_players):

    self.players_list = []

    # remeber values in class variables, not local one
    self.num_of_players = num_of_players
    self.player_num = 0

    # create only one Label - and change text in it
    self.name_label = tk.Label(self.bg_label,
    self.name_label.grid(row=0, padx=200, pady=120)

    # create only one Entry and assign function `self.player_names`
    self.name_entry = tk.Entry(self.bg_label)
    self.name_entry.grid(row=1, padx=200, pady=0)
    self.name_entry.bind('<Return>', self.player_names)

    # set text for first player
    self.player_num += 1
    self.name_label["text"] = 'What is the name of Player {} ?'.format(player_num)

def player_names(self, event):

    # get player's name from Entry                                    
    self.players_list.append(self.name_entry.get())
    self.name_entry.delete(0, 'end')

    # set text for next player or destroy Entry after last player
    self.player_num += 1
    if self.player_num <= self.num_of_players:
        self.name_label["text"] = 'What is the name of Player {} ?'.format(player_num)
    else:
        self.name_label.destroy()                               
        self.name_entry.destroy()

它在其他 GUI(不仅在 tkinter 中)和其他语言(不仅在 Python 中)中的工作方式相同