javascript - 从第 n 个 td 元素中选择数据

Question

我正在尝试从以下 html 中获取数据(“borgid”):

<tr style="cursor:default;" class="odd">
    <td class=" ">1</td>
    <td class=" ">What was your favorite childhood pet's name?</td>
    <td data-borgid="1" class=" ">Generic Hospital Networks</td>
    <td class=" ">5173</td>
    <td style="text-align:right;" class=" "><input type="button" value="Remove" name="1" class="deleteMeCQ" style="cursor:pointer;"></td>
</tr>

我尝试了 $(':nth-child(2)', $(this)).data("borgid") 和 $tds.eq(2)。数据(“borgid”)。两者都返回“未定义”。提前致谢。

另请参阅:Is there a way to combine $(this) with :nth-child?

var a = [];
$("#ChallengeQuestionsTable tbody tr").each(function () {

var $tds = $(this).children('td');

var questionid = '';
var question = '';
var borgid = '';

if ($tds.length == 5) {
    questionid = $tds.eq(0).html();
    question = $tds.eq(1).html();
    borgid = $(':nth-child(2)', $(this)).data("Borgid");

    a.push('{ "questionid" : "' + questionid + '", "question" : "' + question + '", "borgid" : "' + borgid + '" }');
}
});

Answer 1

如果你想获得borgid，可以通过现有属性选择:

borgid = $($(this).find("[data-borgid]").get(0)).attr("data-borgid");