gpt4 book ai didi

r - 可以在R中绘制图表吗?

转载 作者:行者123 更新时间:2023-12-03 12:22:17 24 4
gpt4 key购买 nike

我想知道R中是否有任何包可以使用x,y坐标和形状大小来绘制如下内容:

我有车辆前中心的坐标及其大小(长度和宽度)。

编辑

这是原始数据集的样子:

> head(df)
Vehicle.ID Frame.ID Global.X Global.Y Vehicle.Length Vehicle.width Lane Preceding.Vehicle.ID Following.Vehicle.ID Spacing Headway
1 2 43 6451214 1873261 14.5 4.9 2 0 13 0 0
2 2 44 6451217 1873258 14.5 4.9 2 0 13 0 0
3 2 45 6451220 1873256 14.5 4.9 2 0 13 0 0
4 2 46 6451223 1873253 14.5 4.9 2 0 13 0 0
5 2 47 6451225 1873250 14.5 4.9 2 0 13 0 0
6 2 48 6451228 1873247 14.5 4.9 2 0 13 0 0

对于任何给定的帧,我想可视化间隙,例如,对于帧号。 500:
ff <- subset(df, Frame.ID==500)
qplot(x=Global.X, y=Global.Y, data=ff)

所有这些点都是车辆的前中心坐标。我不知道如何显示每辆车的长度和宽度并标注间隙值。

最佳答案

因此,我不主张您依靠ggplot来执行此操作,因为大多数其他建议的解决方案都可能更好,但是这个问题使我很感兴趣,因为我一直想深入研究ggplot的胆量。这是我设法提出的:

ggplot(df, aes(x=x, y=y, length=length, width=width, fill=label)) +
geom_hline(yintercept=seq(5, 35, by=10), color="white", size=2, linetype=2) +
geom_car() +
coord_equal() +
theme(panel.background = element_rect(fill="#555555"),
panel.grid.major = element_blank(),
panel.grid.minor = element_blank())

enter image description here

您还可以添加带有 geom_segment的箭头或带有 geom_text的显式标签,但是我们将其留给读者练习。

现在,要使其正常工作,我们必须创建 geom_car,尽管如果您不需要详细的图片,则可以使用 geom_rect。这是 geom_car(注意:现在也可以作为 ggbg package的一部分使用):
# Generate a car 'grob' using a baseline PNG

car.raster <- png::readPNG("~/Downloads/car2.png")

# The `grid` grob actually responsible for rendering our car,
# combines our transparent car elements with a background rectangle
# for color/fill.

carGrob <- function(x, y, length, width, gp) {
grid::grobTree(
grid::rectGrob(
x, y, hjust=.5, height=width, width=length,
gp = gp
),
grid::rasterGrob(
car.raster, x=x, y=y, hjust=.5, height=width, width=length
) ) }
# The `ggproto` object that maps our data to the `grid` grobs

GeomCar <- ggplot2::ggproto("GeomCar", ggplot2::Geom,
# Generate grobs from the data, we have to reconvert length/width so
# that the transformations persist

draw_panel=function(self, data, panel_params, coords) {
with(
coords$transform(data, panel_params),
carGrob(
x, y, length=xmax-xmin, width=ymax-ymin,
gp=grid::gpar(
col = colour, fill = alpha(fill, alpha),
lwd = size * .pt, lty = linetype, lineend = "butt"
) ) ) },
# Convert data to coordinates that will get transformed (length/width don't
# normally).

setup_data=function(self, data, params) {
transform(data,
xmin = x - length / 2, xmax = x + length / 2,
ymin = y - width / 2, ymax = y + width / 2
) },
# Required and default aesthetics

required_aes=c("x", "y", "length", "width"),
default_aes = aes(
colour = NA, fill = "grey35", size = 0.5, linetype = 1, alpha = NA
),
# Use the car grob in the legend

draw_key = function(data, params, size) {
with(
data,
carGrob(
0.5, 0.5, length=.75, width=.5,
gp = grid::gpar(
col = colour, fill = alpha(fill, alpha),
lwd = size * .pt, lty = linetype, lineend = "butt"
) ) ) }
)
# External interface

geom_car <- function(
mapping=NULL, data=NULL, ..., inherit.aes=TRUE, show.legend=NA
) {
layer(
data=data, mapping=mapping, geom=GeomCar, position="identity",
stat="identity", show.legend = show.legend, inherit.aes = inherit.aes,
params=list(...)
)
}

汽车:

enter image description here

数据:
df <- read.table(h=T, t="vehicle  x y   length  width   label
1 150 10 14 5 other
2 180 8 12 5 other
3 220 10 18 5 other
4 145 20 15 5 target
5 250 18 14 5 other
6 160 30 13 5 autonomous
7 200 33 15 5 other
8 240 31 22 5 other
")

关于r - 可以在R中绘制图表吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22159087/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com