javascript - JS 检查 2 个对象的相互项

Question

我有 2 个 JS 对象:

第一个:

One = {
   "Sunday": {
      1:false,
      2:false,
      3:true,
      4:false, .... until 24. Each item could be either true or false.
   },
   "Monday": {1:true, 2:false, ....},
   //And so on, 7 days of the week
}

第二个与第一个类似，只是其值(真/假)不同。

我想运行一个函数，它可以告诉我，我不关心如何，哪些项目在两个对象中都具有 true。例如，如果 One.Sunday[2] = true 和 Two.Sunday[2] = true，我想知道这一点。

我希望我说得足够清楚。

如果可能的话，如果同一个函数也可以接受 3 个或更多对象并返回所有对象的共同项，那就太好了。

谢谢，鲁文

Answer 1

var sundayOne = {1:true,2:false,3:false,4:true}; 
var mondayOne = {1:true,2:true,3:false,4:false};
var tuesdayOne = {1:false,2:false,3:true,4:true};
var one = {"sunday":sundayOne,"monday":mondayOne,"tuesday":tuesdayOne}; // two objects having 


var sundayTwo = {1:true,2:true,3:true,4:true}; 
var mondayTwo = {1:false,2:false,3:false,4:false};
var tuesdayTwo = {1:true,2:true,3:true,4:true};
var two = {"sunday":sundayTwo,"monday":mondayTwo,"tuesday":tuesdayTwo};

var matchedArr = []
for(each in one) {
    var obj = {} //create new object
    obj[each] = {} //add new object to store matched each - Sunday, Monday
    for(subEach in one[each]) {
        //value is false so we have to check with undefined
        if(two[each][subEach] != undefined) {
            if(one[each][subEach] == two[each][subEach]) {
                console.log('Match found at ', each, subEach, one[each][subEach])
                obj[each][subEach] = one[each][subEach]
            }
        }
    }
    matchedArr.push(obj)
}
console.log(matchedArr)

//output
[Object, Object, Object]
0: Object
    sunday: Object
        1: true
        4: true
1: Object
    monday: Object
        3: false
        4: false
2: Object
    tuesday: Object
    3: true
        4: true
        length: 3