math - 使用两个经度/纬度点获取方向(罗盘)

Question

我正在为移动设备开发“指南针”。我有以下几点:

point 1 (current location): Latitude = 47.2246, Longitude = 8.8257
point 2 (target  location): Latitude = 50.9246, Longitude = 10.2257

我也有以下信息(来自我的Android手机):

The compass-direction in degree, which bears to the north. 
For example, when I direct my phone to north, I get 0°

如何创建一个“罗盘式”箭头，向我显示该点的方向？
这有数学上的问题吗？
编辑:好的，我找到了一个解决方案，它看起来像这样:

/**
 * Params: lat1, long1 => Latitude and Longitude of current point
 *         lat2, long2 => Latitude and Longitude of target  point
 *         
 *         headX       => x-Value of built-in phone-compass
 * 
 * Returns the degree of a direction from current point to target point
 *
 */
function getDegrees(lat1, long1, lat2, long2, headX) {
    
    var dLat = toRad(lat2-lat1);
    var dLon = toRad(lon2-lon1);

    lat1 = toRad(lat1);
    lat2 = toRad(lat2);

    var y = Math.sin(dLon) * Math.cos(lat2);
    var x = Math.cos(lat1)*Math.sin(lat2) -
            Math.sin(lat1)*Math.cos(lat2)*Math.cos(dLon);
    var brng = toDeg(Math.atan2(y, x));

    // fix negative degrees
    if(brng<0) {
        brng=360-Math.abs(brng);
    }

    return brng - headX;
}

Answer 1

忘了说我终于找到了答案。该应用程序将确定运输车辆及其目的地的指南针方向。本质上，是用于获取地球曲率，查找 Angular /罗盘读数，然后将该 Angular 与通用罗盘值进行匹配的奇特数学。当然，您可以只保持罗盘读数并将其作为图像旋转量。请注意，这是对到达终点(汽车站)的车辆方向的平均确定，这意味着它不知道道路在做什么(因此，这可能最适用于飞机或过山车 Derby )。

//example obj data containing lat and lng points
//stop location - the radii end point
endpoint.lat = 44.9631;
endpoint.lng = -93.2492;

//bus location from the southeast - the circle center
startpoint.lat = 44.95517;
startpoint.lng = -93.2427;

function vehicleBearing(endpoint, startpoint) {
    endpoint.lat = x1;
    endpoint.lng = y1;
    startpoint.lat = x2;
    startpoint.lng = y2;

    var radians = getAtan2((y1 - y2), (x1 - x2));

    function getAtan2(y, x) {
        return Math.atan2(y, x);
    };

    var compassReading = radians * (180 / Math.PI);

    var coordNames = ["N", "NE", "E", "SE", "S", "SW", "W", "NW", "N"];
    var coordIndex = Math.round(compassReading / 45);
    if (coordIndex < 0) {
        coordIndex = coordIndex + 8
    };

    return coordNames[coordIndex]; // returns the coordinate value
}

即:
车辆轴承(mybus，公交车站)
可能返回“NW”，表示其向西北移动