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sql - 是否可以重用子查询?

转载 作者:行者123 更新时间:2023-12-03 12:09:06 24 4
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我在尝试执行查询时遇到了一些问题。我有两个表,一个包含元素信息,另一个包含与第一个表的元素相关的记录。这个想法是在同一行中获取元素信息加上几条记录信息。

结构可以这样解释:

 table [ id, name ]
[1, '1'], [2, '2']

table2 [ id, type, value ]
[1, 1, '2009-12-02']
[1, 2, '2010-01-03']
[1, 4, '2010-01-03']
[2, 1, '2010-01-02']
[2, 2, '2010-01-02']
[2, 2, '2010-01-03']
[2, 3, '2010-01-07']
[2, 4, '2010-01-07']

这是我想要实现的目标:
 result [id, name, Column1, Column2, Column3, Column4]

[1, '1', '2009-12-02', '2010-01-03', , '2010-01-03']
[2, '2', '2010-01-02', '2010-01-02', '2010-01-07', '2010-01-07']

以下查询获得了正确的结果,但在我看来效率极低,必须为每一列迭代 table2。无论如何都可以做一个子查询并重用它吗?
SELECT
a.id,
a.name,
(select min(value) from table2 t where t.id = subquery.id and t.type = 1 group by t.type) as Column1,
(select min(value) from table2 t where t.id = subquery.id and t.type = 2 group by t.type) as Column2,
(select min(value) from table2 t where t.id = subquery.id and t.type = 3 group by t.type) as Column3,
(select min(value) from table2 t where t.id = subquery.id and t.type = 4 group by t.type) as Column4
FROM
(SELECT distinct id
FROM table2 t
WHERE (t.type in (1, 2, 3, 4))
AND t.value between '2010-01-01' and '2010-01-07') as subquery
LEFT JOIN table a ON a.id = subquery.id

最佳答案

您可以将聚合取出到 CTE(公用表表达式)中:

with minima as (select t.id, t.type, min(value) min_value
from table2 t
where t.type in (1,2,3,4)
group by t.id, t.type)
select a.id, a.name,
(select min_value from minima where minima.id = subquery.id and minima.type = 1) as column1,
(select min_value from minima where minima.id = subquery.id and minima.type = 2) as column2,
(select min_value from minima where minima.id = subquery.id and minima.type = 3) as column3,
(select min_value from minima where minima.id = subquery.id and minima.type = 4) as column4
from (select distinct id from table2 t where t.type in (1,2,3,4) and t.value between '2010-01-01' and '2010-01-07') as subquery
left join a on a.id = subquery.id

当然,这是否真的有任何好处(甚至支持)取决于您的环境和数据集。

另一种方法:
select xx.id, a.name, xx.column1, xx.column2, xx.column3, xx.column4
from (
select id,
max(case type when 1 then min_value end) as column1,
max(case type when 2 then min_value end) as column2,
max(case type when 3 then min_value end) as column3,
max(case type when 4 then min_value end) as column4
from (select t.id, t.type, min(value) min_value
from table2 t
where t.type in (1,2,3,4)
group by t.id, t.type) minima
group by id
) xx left join a on a.id = xx.id
order by 1

关于sql - 是否可以重用子查询?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2686919/

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