sockets - 在事件之间将属性附加到套接字

Question

我发现我可以将名称等附加到socket.io套接字。

这很好。

但是我想在另一个事件上检索相同的数据。

这应该显示得很清楚:

socket.on('studentJoinRoom', function answerStudentJoin(msg) {

    var userName = msg.userName;
    var roomId = msg.roomId;

    console.log('user ' + userName + ' joining room ' + roomId);
    socket.userName = userName;

    if (socket.room !== roomId) {  // only join once
      socket.room = roomId;
      testRooms.joinClient(userName, roomId);
      socket.join(roomId); // join socket room
      socket.emit('studentJoinConfirmed');
      socket.broadcast.to(testRooms.getTeacherId(roomId)).emit('newStudentJoined', {student: userName});
    }
    console.dir(testRooms.getRooms());
});


socket.on('disconnect', function(socket) {
    console.log(socket.userName + ' has left the room ' + socket.room);
})

我想从 on('studentJoinRoom'内的 on('disconnect访问数据。我怎样才能做到这一点？

控制台输出:

user test joining room ijzvqmau
{ ijzvqmau: 
   { Id: 'ijzvqmau',
     teacherName: 'testteacher',
     teacherId: '/#KMGUyCINopRDvf5JAAAE',
     clients: [ 'test' ] } }
undefined has left the room undefined

Answer 1

您一定不要传递给回调函数'socket'，因此只需将其删除即可:

socket.on('disconnect', function() {
   console.log(socket.userName + ' has left the room ' + socket.room);
 })