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amazon-dynamodb - 错误 InvalidParameterType : Expected params. 项目 ['pid'] 成为 DynamoDB 中的结构

转载 作者:行者123 更新时间:2023-12-03 12:02:41 25 4
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注意:所有这些都发生在 DynamoDB 的本地实例上。

这是我用来从 DynamoDB Shell 创建表的代码:

var params = {
TableName: "TABLE-NAME",
KeySchema: [
{ AttributeName: "pid",
KeyType: "HASH"
}
],
AttributeDefinitions: [
{ AttributeName: "pid",
AttributeType: "S"
}
],
ProvisionedThroughput: {
ReadCapacityUnits: 1,
WriteCapacityUnits: 1
}
};


dynamodb.createTable(params, function(err, data) {
if (err)
console.log(JSON.stringify(err, null, 2));
else
console.log(JSON.stringify(data, null, 2));
});

这是被调用以将元素添加到数据库中的函数(在 node.js 中):
function(request, response) {
params = {
TableName: 'TABLE-NAME',
Item: {
pid: 'abc123'
}
};
console.log(params);
dynamodb.putItem(params, function(err, data) {
if (err)
console.log(JSON.stringify(err, null, 2));
else
console.log(JSON.stringify(data, null, 2));
});
}

我得到的输出是:
{ TableName: 'TABLE-NAME',
Item: { pid: 'abc123' } } // THIS IS PARAMS
{
"message": "There were 7 validation errors:\n* InvalidParameterType: Expected params.Item['pid'] to be a structure\n* UnexpectedParameter: Unexpected key '0' found in params.Item['pid']\n* UnexpectedParameter: Unexpected key '1' found in params.Item['pid']\n* UnexpectedParameter: Unexpected key '2' found in params.Item['pid']\n* UnexpectedParameter: Unexpected key '3' found in params.Item['pid']\n* UnexpectedParameter: Unexpected key '4' found in params.Item['pid']\n* UnexpectedParameter: Unexpected key '5' found in params.Item['pid']",
"code": "MultipleValidationErrors",
"errors": [
{
"message": "Expected params.Item['pid'] to be a structure",
"code": "InvalidParameterType",
"time": "2015-11-26T15:51:33.932Z"
},
{
"message": "Unexpected key '0' found in params.Item['pid']",
"code": "UnexpectedParameter",
"time": "2015-11-26T15:51:33.933Z"
},
{
"message": "Unexpected key '1' found in params.Item['pid']",
"code": "UnexpectedParameter",
"time": "2015-11-26T15:51:33.933Z"
},
{
"message": "Unexpected key '2' found in params.Item['pid']",
"code": "UnexpectedParameter",
"time": "2015-11-26T15:51:33.933Z"
},
{
"message": "Unexpected key '3' found in params.Item['pid']",
"code": "UnexpectedParameter",
"time": "2015-11-26T15:51:33.933Z"
},
{
"message": "Unexpected key '4' found in params.Item['pid']",
"code": "UnexpectedParameter",
"time": "2015-11-26T15:51:33.934Z"
},
{
"message": "Unexpected key '5' found in params.Item['pid']",
"code": "UnexpectedParameter",
"time": "2015-11-26T15:51:33.934Z"
}
],
"time": "2015-11-26T15:51:33.944Z"
}

我不明白为什么或如何获取键 0、1、2、3、4 和 5,而它们在上一行打印时不存在。

另外,如何修复错误 Expected params.Item['pid'] to be a structure ?我已将其声明为字符串并尝试存储字符串!

其他注意事项:
当我在 shell 上运行它时,我在函数中使用的相同代码工作得很好。我还包括了 aws-sdk 并根据需要对其进行了配置:
var AWS = require('aws-sdk');
AWS.config.region = 'us-east-1';
AWS.config.endpoint = 'http://localhost:8000/'
var dynamodb = new AWS.DynamoDB();

最佳答案

putItem() AWS.DynamoDB 上的方法类(class)期待 params.Item要格式化为 AttributeValue 表示的对象。这意味着你必须改变这个:

params = {
TableName: 'TABLE-NAME',
Item: {
pid: 'abc123'
}
};

进入这个:

params = {
TableName: 'TABLE-NAME',
Item: {
pid: {
S: 'abc123'
}
}
};

如果你想使用原生 javascript 对象,你应该使用 AWS.DynamoDB.DocumentClient 类,它会自动将 Javascript 类型编码到 DynamoDB AttributeValues 上,如下所示:
  • 字符串 -> S
  • 号码 -> N
  • bool 值 -> bool 值
  • 空 -> 空
  • 数组 -> L
  • 对象 -> M
  • 缓冲区、文件、Blob、ArrayBuffer、DataView 和 JavaScript 类型数组 -> B

  • 它提供了 put() 方法,委托(delegate)给 AWS.DynamoDB.putItem() .

    关于amazon-dynamodb - 错误 InvalidParameterType : Expected params. 项目 ['pid'] 成为 DynamoDB 中的结构,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33942945/

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