c# - .NET 相当于 recv？

Question

我有一部分 C 代码正在尝试移植到 C#。

在我的 C 代码中，我创建了一个套接字，然后发出一个接收命令。接收命令是

void receive(mysocket, char * command_buffer)
{
    recv(mysocket, command_buffer, COMMAND_BUFFER_SIZE, 0);
}

现在，命令缓冲区返回新值，包括 command_buffer[8]作为指向字符串的指针。

我真的很困惑如何在 .NET 中执行此操作，因为 .NET Read() 方法专门接收字节而不是字符。重要的部分是我得到了指向字符串的指针。

有任何想法吗？

Answer 1

Socket Send and Receive C#

Socket.Receive 方法

Receive 方法从绑定(bind)的 Socket 接收数据到您的缓冲区。方法
返回接收的字节数。如果套接字缓冲区为空
会发生错误。您应该尝试接收
以后的数据。

以下方法尝试将 size 字节接收到缓冲区中以
偏移位置。如果操作持续时间超过超时
毫秒它会引发异常。

public static void Receive(Socket socket, byte[] buffer, int offset, int size, int timeout)
{
  int startTickCount = Environment.TickCount;
  int received = 0;  // how many bytes is already received
  do {
    if (Environment.TickCount > startTickCount + timeout)
      throw new Exception("Timeout.");
    try {
      received += socket.Receive(buffer, offset + received, size - received, SocketFlags.None);
    }
    catch (SocketException ex)
    {
      if (ex.SocketErrorCode == SocketError.WouldBlock ||
          ex.SocketErrorCode == SocketError.IOPending ||
          ex.SocketErrorCode == SocketError.NoBufferSpaceAvailable)
      {
        // socket buffer is probably empty, wait and try again
        Thread.Sleep(30);
      }
      else
        throw ex;  // any serious error occurr
    }
  } while (received < size);
}

Call the Receive method using code such this:
[C#]

Socket socket = tcpClient.Client;
byte[] buffer = new byte[12];  // length of the text "Hello world!"
try
{ // receive data with timeout 10s
  SocketEx.Receive(socket, buffer, 0, buffer.Length, 10000);
  string str = Encoding.UTF8.GetString(buffer, 0, buffer.Length);
}
catch (Exception ex) { /* ... */ }