c# - C#在套接字中发送屏幕截图

Question

自一周以来，我一直在尝试从客户端PC制作屏幕截图并将其发送到服务器。

好吧，它现在工作了一点，但还不完全。我尝试了几种在Internet上找到的脚本，但是没有一个能按我的意愿工作，所以我更改了它们，但是由于我对套接字的了解很少，所以我无法正确使用它。你们能帮我吗？

屏幕截图功能可以正常工作，但是当我将流发送到服务器时，它仅接收图像的顶部(例如:原始屏幕截图为150kb，但是我接收的文件仅为40kb)请尝试其他几种文件发送脚本，但是我最多只能收到6个字节。

当我尝试使用While函数时，它什么也不发送给我或1kb，所以我知道我做错了什么，但是呢？

这是我的服务器代码:

private void bgWorker_DoWork(object sender, DoWorkEventArgs e)
    {
        try
        {
            IPEndPoint ipEnd = new IPEndPoint(IPAddress.Any, 5656);
            Socket sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
            sock.Bind(ipEnd);
            sock.Listen(100);
            Socket clientSock = sock.Accept();

            byte[] clientData = new byte[1024 * 5000];
            string receivedPath = "C:/";

            int receivedBytesLen = clientSock.Receive(clientData);

            int fileNameLen = BitConverter.ToInt32(clientData, 0);
            string fileName = Encoding.ASCII.GetString(clientData, 4, fileNameLen);

            konjo = "Client: " + clientSock.RemoteEndPoint + "connected & File: " + fileName + " started received.";

            BinaryWriter bWrite = new BinaryWriter(File.Open(receivedPath + fileName, FileMode.Append)); ;
            bWrite.Write(clientData, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen);

            status = "File: " + fileName + "Received & Saved at path: " + receivedPath;

            bWrite.Close();
            clientSock.Close();
        }
        catch (Exception ex)
        {
            status = "Failed: " + ex.Message;
        }
    }

    private void bgWorker_Complete(object sender, RunWorkerCompletedEventArgs e)
    {
        label1.Text = status;

    }

这是我的客户代码:

        private void bgsender_work(object sender, DoWorkEventArgs e)
    {
        try
        {
            int screenWidth = Screen.GetBounds(new Point(0, 0)).Width;
            int screenHeight = Screen.GetBounds(new Point(0, 0)).Height;
            Bitmap bmpScreenShot = new Bitmap(screenWidth, screenHeight);
            Graphics gfx = Graphics.FromImage((Image)bmpScreenShot);
            gfx.CopyFromScreen(0, 0, 0, 0, new Size(screenWidth, screenHeight));
            MemoryStream test = new MemoryStream();
            bmpScreenShot.Save(test, ImageFormat.Jpeg);
            bmpScreenShot.Save("C:\\Clienttest.jpeg", ImageFormat.Jpeg);

            IPAddress[] ipAddress = Dns.GetHostAddresses(Dns.GetHostName());
            IPEndPoint ipEnd = new IPEndPoint(ipAddress[2], 5656);
            Socket clientSock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);


            string fileName = "screenshot.Jpeg";
            string filePath = "Your File Path";
            byte[] fileNameByte = Encoding.ASCII.GetBytes(fileName);
            byte[] Data = test.ToArray();
            byte[] clientData = new byte[4 + fileNameByte.Length + Data.Length];
            byte[] fileNameLen = BitConverter.GetBytes(fileNameByte.Length);

            fileNameLen.CopyTo(clientData, 0);
            fileNameByte.CopyTo(clientData, 4);
            Data.CopyTo(clientData, 4 + fileNameByte.Length);

            clientSock.Connect("192.168.1.15", 5656);
            clientSock.Send(clientData);

            status = "File: " + fileName + " has been sent.";
            clientSock.Close();
            Console.ReadLine();
        }
        catch (Exception ex)
        {
            status = "It failed: " + ex.Message;
        }

    }

    private void bgsender_complete(object sender, RunWorkerCompletedEventArgs e)
    {
        label1.Text = status;
    }

Answer 1

我为客户端-服务器应用程序编写了一些示例代码，似乎可以满足您对另一个问题的回答。

看一下:https://stackoverflow.com/a/5575287/381588，它可以正常工作，并且很容易适应您的需求。