c# - 当有多个服务器广播时，客户端如何接收多个广播消息？

Question

我正在使用 system.Net.Socket 从服务器向客户端发送和接收消息。但是当多个服务器广播消息然后接收器程序突然关闭时遇到问题。

我的广播服务器代码如下..

using System;
using System.Net;
using System.Net.Sockets;
using System.Text;

public class Broadcst
{
    public static void Main()
    {
        Socket sock = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
        IPEndPoint iep1 = new IPEndPoint(IPAddress.Broadcast, 9050);
        IPEndPoint iep2 = new IPEndPoint(IPAddress.Parse("192.168.1.255"), 9050);

        string hostname = Dns.GetHostName();
        byte[] data = Encoding.ASCII.GetBytes(hostname);

        sock.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.Broadcast, 1);
        sock.SendTo(data, iep1);
        sock.SendTo(data, iep2);
        sock.Close();
    }
}

我的接收方代码如下所示...

  using System;
    using System.Net;
    using System.Net.Sockets;
    using System.Text;

    public class RecvBroadcst
    {
        public static void Main()
        {
            Socket sock = new Socket(AddressFamily.InterNetwork,
                            SocketType.Dgram, ProtocolType.Udp);

While(true){
  IPEndPoint iep = new IPEndPoint(IPAddress.Any, 9050);
            sock.Bind(iep);
            EndPoint ep = (EndPoint)iep;
            Console.WriteLine("Ready to receive...");

            byte[] data = new byte[1024];
            int recv = sock.ReceiveFrom(data, ref ep);
            string stringData = Encoding.ASCII.GetString(data, 0, recv);
            Console.WriteLine("received: {0}  from: {1}",
                                  stringData, ep.ToString());

            data = new byte[1024];
            recv = sock.ReceiveFrom(data, ref ep);
            stringData = Encoding.ASCII.GetString(data, 0, recv);
            Console.WriteLine("received: {0}  from: {1}",
                                  stringData, ep.ToString());

}
            sock.Close();
        }
    }

那么当有多个服务器广播时，客户端如何接收多个广播消息呢？

当我再次从服务器发送消息时，它会抛出错误，例如“每个套接字地址(协议(protocol)/网络地址/端口)通常只允许使用一次”

Answer 1

您调用Bind在同一个 Socket 实例上多次使用相同的参数(每次迭代一个)。您应该调用 Bind一次。