php - PHP的简单服务器/客户端(UDP，数据报)无法看到对方

Question

服务器:

 $address = '127.0.0.1';
 $port = 46123;
 if (($sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) === false) {
     echo "socket_create() failed: reason: " . socket_strerror(socket_last_error()) . "\n"; die;
 }
 echo 'socket_create OK '.$address.':'.$port."\n";
 if (socket_bind($sock, $address, $port) === false) {
     echo "socket_bind() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n"; die;
 }
 if (socket_listen($sock, 5) === false) {
     echo "socket_listen() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n"; die;
 }

 do {
     if (($msgsock = socket_accept($sock)) === false) {
         echo "socket_accept() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n";
         break;
     }

客户:

$socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP);
$in = ';lsdkf';
var_dump (socket_sendto($socket, $in,strlen($in), 0,'127.0.0.1',46123));

客户端说确定，但服务器未收到该消息。我究竟做错了什么？

Answer 1

您的服务器实际上不是UDP服务器。代替

if (($sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) === false) {

和

if (($sock = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP)) === false) {

并使用 socket_recvfrom 代替 socket_accept(这对UDP服务器没有意义)。