没有最终修剪的 Groovy 拆分

Question

我正在解析一个 CVS 文件，如下所示:

"07555555555",25.70,18/11/2010,01/03/2011,N,133,0,36,,896,537,547,,Mr,John,Doe,,
"07555555555",10.15,26/01/2011,01/03/2011,N,16,0,100,,896,537,547,,Mrs,Jane,Doe,,jane@doe.com

问题是当使用这样的脚本时:

file.eachLine{ line ->

    items = line.split(",")
    println items.length
}

结果如下所示:

16
18

这让我觉得 拆分 函数删除最终值。我需要它来拥有所有元素，即使它们是空的。任何的想法？

Answer 1

我想你想做:

items = line.split(',', -1)

确保您获得所有 token

(根据 the javadoc ):

The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array's length will be no greater than n, and the array's last entry will contain all input beyond the last matched delimiter. If n is non-positive then the pattern will be applied as many times as possible and the array can have any length. If n is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.