rust - 按字符读取输入字符

Question

我有以下函数来读取用户输入 char来自 char .通过缓冲 char在数组中，我想要一个字符串但到目前为止失败并出现错误:

expected 'char', found enum termion::event::Key

fn readtest() {
    let terminal = io::stdout().into_raw_mode();
    let mut stdout = terminal.unwrap();

    // Use asynchronous stdin
    let mut stdin = termion::async_stdin().keys();
    let mut s = String::new();

    loop {
        // Read input (if any)
        let input = stdin.next();

        // If a key was pressed
        if let Some(Ok(key)) = input {
            match key {
                // Exit if 'q' is pressed
                termion::event::Key::Char('q') => break,
                // Else print the pressed key
                _ => {
                    s.push(key);
                    stdout.lock().flush().unwrap();
                }
            }
        }
        thread::sleep(time::Duration::from_millis(50));
    }
    s
}

Answer 1

s 是 String和关键是一个 Char(char) .您不能将键直接插入 s。您首先需要使用匹配模式，如下所示:

 if let termion::event::Key::Char(k) = key {
       s.push(k);
 }